The graph of the path of a cannonball fired in the air is shown to the right. in 26500- The three red points that it passes through are: (660, 19530), (1010, 18480), and (1080, 15330) 1.) Which of the following equations below match the path of this cannonball? 40 15 x feet OA. O B. y=- 10 + 164x - 45150 y= - 10 + 164x + 45300 Oc. OD. 1 y%3D + 164x - 132270 - 164x + 171330 10 2.) Using the correct equation above, what values of x was the cannonball on the ground? (Smallest x value) x1 = 0 (Largest x value) x2 =0 y feet

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The graph of the path of a cannonball fired in the
air is shown to the right.
26500-
The three red points that
passes through are:
(660, 19530), (1010, 18480), and (1080, 15330)
1.) Which of the following equations below match
the path of this cannonball?
40
1550
x feet
O A.
1
+ 164x - 45150
OB.
y:
2+ 164x + 45300
10
y= -
10
Oc.
1
OD.
1
10X - 164x + 171330
x2 + 164x - 132270
10
y= -
y =
2.) Using the correct equation above, what values of x was the cannonball on the ground?
(Smallest x value) x1 =
(Largest x value) x2 =
3.) Using the correct equation, What is the maximum height of this projectile?
Maximum height =
feet
Transcribed Image Text:The graph of the path of a cannonball fired in the air is shown to the right. 26500- The three red points that passes through are: (660, 19530), (1010, 18480), and (1080, 15330) 1.) Which of the following equations below match the path of this cannonball? 40 1550 x feet O A. 1 + 164x - 45150 OB. y: 2+ 164x + 45300 10 y= - 10 Oc. 1 OD. 1 10X - 164x + 171330 x2 + 164x - 132270 10 y= - y = 2.) Using the correct equation above, what values of x was the cannonball on the ground? (Smallest x value) x1 = (Largest x value) x2 = 3.) Using the correct equation, What is the maximum height of this projectile? Maximum height = feet
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