The graph of the path of a cannonball fired in the air is shown to the right. in 26500- The three red points that it passes through are: (660, 19530), (1010, 18480), and (1080, 15330) 1.) Which of the following equations below match the path of this cannonball? 40 15 x feet OA. O B. y=- 10 + 164x - 45150 y= - 10 + 164x + 45300 Oc. OD. 1 y%3D + 164x - 132270 - 164x + 171330 10 2.) Using the correct equation above, what values of x was the cannonball on the ground? (Smallest x value) x1 = 0 (Largest x value) x2 =0 y feet
The graph of the path of a cannonball fired in the air is shown to the right. in 26500- The three red points that it passes through are: (660, 19530), (1010, 18480), and (1080, 15330) 1.) Which of the following equations below match the path of this cannonball? 40 15 x feet OA. O B. y=- 10 + 164x - 45150 y= - 10 + 164x + 45300 Oc. OD. 1 y%3D + 164x - 132270 - 164x + 171330 10 2.) Using the correct equation above, what values of x was the cannonball on the ground? (Smallest x value) x1 = 0 (Largest x value) x2 =0 y feet
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Concept explainers
Rate of Change
The relation between two quantities which displays how much greater one quantity is than another is called ratio.
Slope
The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as:
Question

Transcribed Image Text:The graph of the path of a cannonball fired in the
air is shown to the right.
26500-
The three red points that
passes through are:
(660, 19530), (1010, 18480), and (1080, 15330)
1.) Which of the following equations below match
the path of this cannonball?
40
1550
x feet
O A.
1
+ 164x - 45150
OB.
y:
2+ 164x + 45300
10
y= -
10
Oc.
1
OD.
1
10X - 164x + 171330
x2 + 164x - 132270
10
y= -
y =
2.) Using the correct equation above, what values of x was the cannonball on the ground?
(Smallest x value) x1 =
(Largest x value) x2 =
3.) Using the correct equation, What is the maximum height of this projectile?
Maximum height =
feet
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