The graph of f(t) is given below: 16 1,8 = 1.8 (Click on graph to enlarge) a. Represent f(t) using a combination of Heaviside step functions. Use h(t - a) for the Heaviside function shifted a units horizontally. f(t) = 3(t-1)h(t-1)-3(t-6)h(t-6)-15h(t-8) b. Find the Laplace transform F(s) = L{f(t)} for s + 0. F(s) = L{f(t)} (3e^(-5)-3e^(-69)-159e^(-5))/s^2 help (formulas) help (formulas)
The graph of f(t) is given below: 16 1,8 = 1.8 (Click on graph to enlarge) a. Represent f(t) using a combination of Heaviside step functions. Use h(t - a) for the Heaviside function shifted a units horizontally. f(t) = 3(t-1)h(t-1)-3(t-6)h(t-6)-15h(t-8) b. Find the Laplace transform F(s) = L{f(t)} for s + 0. F(s) = L{f(t)} (3e^(-5)-3e^(-69)-159e^(-5))/s^2 help (formulas) help (formulas)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![The graph of f(t) is given below:
16
1,8
=
1.8
(Click on graph to enlarge)
a. Represent f(t) using a combination of Heaviside step functions. Use h(t - a) for the Heaviside function shifted a units
horizontally.
f(t) = 3(t-1)h(t-1)-3(t-6)h(t-6)-15h(t-8)
b. Find the Laplace transform F(s) = L{f(t)} for s + 0.
F(s) = L{f(t)}
(3e^(-5)-3e^(-69)-159e^(-5))/s^2
help (formulas)
help (formulas)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fadf6522a-836e-432f-b2da-01517f4c2c07%2F319fd7f5-b9a8-403f-98cd-6f35ce5a73a6%2Fzewignk_processed.png&w=3840&q=75)
Transcribed Image Text:The graph of f(t) is given below:
16
1,8
=
1.8
(Click on graph to enlarge)
a. Represent f(t) using a combination of Heaviside step functions. Use h(t - a) for the Heaviside function shifted a units
horizontally.
f(t) = 3(t-1)h(t-1)-3(t-6)h(t-6)-15h(t-8)
b. Find the Laplace transform F(s) = L{f(t)} for s + 0.
F(s) = L{f(t)}
(3e^(-5)-3e^(-69)-159e^(-5))/s^2
help (formulas)
help (formulas)
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