The graph of f is shown for the interval [-2, 6]. 45 40 35 30 25 20 15 10 5 0 54 y x' -3 -2 -1 0 1 2 3 4 5 6 7 8 For which interval is f' < 0 and f" > 0? ○ (-2,0) ○ (0,2) ○ (2,4) ○ (4,6)

How do the graphs of the functions f(x)=x2 and f(x)=x21 differ? We graphed them at the start of this section. What is the difference between their graphs? How are their graphs the same?

Describe all numbers x that are at a distance of 12 from the number - 4. Express this using absolute value notation.

Use a graphing utility to graph f(x)=10|x-|2 on the viewing window [0,4] . Identify the corresponding range. Show the graph.

Find the domain and sketch the graph of the function.

The domain of the function 11x + 7 is I- 3 f(x) R-{11} OR-(7) OR-(3) R-(0} Question 18 Not yet answered Marked out of 1.00

Find the slope of the graph of the function at the given value. f(x)=-4x²+6x- when x=-3 O a) f(-3)= 802 9 802 b) f(-3)=-- 27 802 27 c) f(-3)=- d) f'(-3)=- e) f(-3)= 802 802 3

The one-to-one functions g and h are defined as follows. g={(-5, 8), (2, −7), (7, 4), (9, 7)} h(x)=3x+14 Find the following. -1 9 (7) = ] -1 11(x) = 0 -(9-)("..-") =

Differentiate the following function. y=x(x5 + 5) 3 Choose the correct setup below to differentiate the function. d d o x(+5)3]-x)((5+5)3)+ ((x5+5)3)·유씨 Ix(x + 5)°]= (x) • ((x5 + 5) ³) - ((x³ + 5)³) • ) d Ix(x5 +5)³]=2•[x(x° +5)³]•[x (x5 + 5)³] dx d Ix(x* + 5)°]= « • 3Ca +5) + ((x³ +5) ³) • ^) d x(x* + 5)³]= « • + ( (x³ + 5)³) • (5 +5) °) (x) + ( (x5 + 5)³) ·– (x5 +5) 3)