The graph of a quadratic function f is given. f(x) = -x2 + 8x -7 y 1 (a) Find the coordinates of the vertex and the x- and y-intercepts. vertex (x, y) = x-intercepts (x, y) = (smaller x-value) (x, y) = (larger x-value) y-intercept (x, y) = (b) Find the maximum or minimum value of f. The -Select--V value of f is f(x) = (c) Find the domain and range of f. (Enter your answers using interval notation.) domain range

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### Quadratic Functions: Finding Key Features

#### The graph of a quadratic function \( f \) is given.

\[ f(x) = -x^2 + 8x - 7 \]

![Graph of quadratic function](image_url) 

*Explanation of the Graph:* 
The given quadratic function \( f(x) = -x^2 + 8x - 7 \) is represented by a downward-facing parabola on the coordinate plane. The vertex of the parabola is a point where the graph reaches its maximum value since the parabola opens downwards. The x- and y-intercepts are the points where the graph intersects the x-axis and y-axis, respectively.

**(a) Find the coordinates of the vertex and the x- and y-intercepts.**

- **Vertex**: The vertex of the quadratic function is the highest or lowest point of the parabola. For the function in standard form \( f(x) = ax^2 + bx + c \), the x-coordinate of the vertex can be found using \( x = -\frac{b}{2a} \).

  \[
  (x, y) = \left( [ \ ], [ \ ] \right)
  \]

- **x-intercepts**: The points where the graph intersects the x-axis. Solve the equation \( -x^2 + 8x - 7 = 0 \) to find the x-intercepts.

  \[
  (x, y) = \left( [ \ ], 0 \right) \quad \text{(smaller x-value)}
  \]

  \[
  (x, y) = \left( [ \ ], 0 \right) \quad \text{(larger x-value)}
  \]

- **y-intercept**: The point where the graph intersects the y-axis. This can be found by evaluating the function at \( x = 0 \).

  \[
  (x, y) = \left( 0, [ \ ] \right)
  \]

**(b) Find the maximum or minimum value of \( f \).**

Since the parabola opens downward, the function \( f \) has a maximum value at the vertex.

The [Select] value of \( f \) is \( f(x) = [ \] \).

**(c) Find the domain and range of \( f \).** (Enter your answers
Transcribed Image Text:### Quadratic Functions: Finding Key Features #### The graph of a quadratic function \( f \) is given. \[ f(x) = -x^2 + 8x - 7 \] ![Graph of quadratic function](image_url) *Explanation of the Graph:* The given quadratic function \( f(x) = -x^2 + 8x - 7 \) is represented by a downward-facing parabola on the coordinate plane. The vertex of the parabola is a point where the graph reaches its maximum value since the parabola opens downwards. The x- and y-intercepts are the points where the graph intersects the x-axis and y-axis, respectively. **(a) Find the coordinates of the vertex and the x- and y-intercepts.** - **Vertex**: The vertex of the quadratic function is the highest or lowest point of the parabola. For the function in standard form \( f(x) = ax^2 + bx + c \), the x-coordinate of the vertex can be found using \( x = -\frac{b}{2a} \). \[ (x, y) = \left( [ \ ], [ \ ] \right) \] - **x-intercepts**: The points where the graph intersects the x-axis. Solve the equation \( -x^2 + 8x - 7 = 0 \) to find the x-intercepts. \[ (x, y) = \left( [ \ ], 0 \right) \quad \text{(smaller x-value)} \] \[ (x, y) = \left( [ \ ], 0 \right) \quad \text{(larger x-value)} \] - **y-intercept**: The point where the graph intersects the y-axis. This can be found by evaluating the function at \( x = 0 \). \[ (x, y) = \left( 0, [ \ ] \right) \] **(b) Find the maximum or minimum value of \( f \).** Since the parabola opens downward, the function \( f \) has a maximum value at the vertex. The [Select] value of \( f \) is \( f(x) = [ \] \). **(c) Find the domain and range of \( f \).** (Enter your answers
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