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The graph of a particle's velocity v(t), is shown below. Time is in seconds, and velocity is in m/s. v(t) 1 0 L Area = 2.3 Area = 1.0 5 Sº 0 Let s(t) be the particle's position at the time t. then the position of the particle at t=5. v(t) dt represents the velocity of the particle at t=5. the total change of velocity in the first five seconds v(5) — v(0) the net distance the particle traveled in the first five seconds s(5) — s(0).

The graph of a particle's velocity v(t), is shown below. Time is in seconds, and velocity is in m/s. v(t) 1 0 L Area = 2.3 Area = 1.0 5 Sº 0 Let s(t) be the particle's position at the time t. then the position of the particle at t=5. v(t) dt represents the velocity of the particle at t=5. the total change of velocity in the first five seconds v(5) — v(0) the net distance the particle traveled in the first five seconds s(5) — s(0).

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The graph of a particle's velocity v(t), is shown below. Time is in seconds, and velocity is in m/s. v(t) 1 0 -1 Area = 2.3 Area = 1.0 Let s(t) be the particle's position at the time t. then the net distance the particle [²v (t) dt the velocity of the particle at t=5. the total change of velocity in the first five seconds v(5) — v(0) represents the position of the particle at t=5. traveled in the first five seconds 8(5) — s(0).
Transcribed Image Text:The graph of a particle's velocity v(t), is shown below. Time is in seconds, and velocity is in m/s. v(t) 1 0 -1 Area = 2.3 Area = 1.0 Let s(t) be the particle's position at the time t. then the net distance the particle [²v (t) dt the velocity of the particle at t=5. the total change of velocity in the first five seconds v(5) — v(0) represents the position of the particle at t=5. traveled in the first five seconds 8(5) — s(0).
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