The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1600 and the standard deviation is $110. 1270 1380 1490 1600 1710 1820 Distribution of Prices What is the approximate percentage of buyers who paid more than $1820? 1930 What is the approximate percentage of buyers who paid between $1490 and $1600? What is the approximate percentage of buyers who paid between $1270 and $1600? What is the approximate percentage of buyers who paid between $1490 and $1710? What is the approximate percentage of buyers who paid less than $1270? What is the approximate percentage of buyers who paid between $1600 and $1820?
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1600 and the standard deviation is $110. 1270 1380 1490 1600 1710 1820 Distribution of Prices What is the approximate percentage of buyers who paid more than $1820? 1930 What is the approximate percentage of buyers who paid between $1490 and $1600? What is the approximate percentage of buyers who paid between $1270 and $1600? What is the approximate percentage of buyers who paid between $1490 and $1710? What is the approximate percentage of buyers who paid less than $1270? What is the approximate percentage of buyers who paid between $1600 and $1820?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### Normal Distribution of HD Television Prices
The graph shows a normal distribution representing the prices paid for a specific model of HD television. Key statistics include:
- **Mean Price:** $1600
- **Standard Deviation:** $110
#### Graph Explanation
The graph is a bell curve illustrating the distribution of prices along the x-axis, ranging from $1270 to $1930. The peak of the curve corresponds to the mean price of $1600. The standard deviation helps determine the spread of the prices around the mean.
### Questions
1. **What is the approximate percentage of buyers who paid more than $1820?**
[Answer box]
2. **What is the approximate percentage of buyers who paid between $1490 and $1600?**
[Answer box]
3. **What is the approximate percentage of buyers who paid between $1270 and $1600?**
[Answer box]
4. **What is the approximate percentage of buyers who paid between $1490 and $1710?**
[Answer box]
5. **What is the approximate percentage of buyers who paid less than $1270?**
[Answer box]
6. **What is the approximate percentage of buyers who paid between $1600 and $1820?**
[Answer box]
This distribution is useful for analyzing purchasing patterns and understanding how prices vary among buyers for this HD television model.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fee710977-90c8-4f84-9cb1-1102aa3efb9b%2Fb6e694a9-b6b2-4736-ae9e-13e78b4c57fd%2Fseq53gs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Normal Distribution of HD Television Prices
The graph shows a normal distribution representing the prices paid for a specific model of HD television. Key statistics include:
- **Mean Price:** $1600
- **Standard Deviation:** $110
#### Graph Explanation
The graph is a bell curve illustrating the distribution of prices along the x-axis, ranging from $1270 to $1930. The peak of the curve corresponds to the mean price of $1600. The standard deviation helps determine the spread of the prices around the mean.
### Questions
1. **What is the approximate percentage of buyers who paid more than $1820?**
[Answer box]
2. **What is the approximate percentage of buyers who paid between $1490 and $1600?**
[Answer box]
3. **What is the approximate percentage of buyers who paid between $1270 and $1600?**
[Answer box]
4. **What is the approximate percentage of buyers who paid between $1490 and $1710?**
[Answer box]
5. **What is the approximate percentage of buyers who paid less than $1270?**
[Answer box]
6. **What is the approximate percentage of buyers who paid between $1600 and $1820?**
[Answer box]
This distribution is useful for analyzing purchasing patterns and understanding how prices vary among buyers for this HD television model.
Expert Solution

Step 1
Since you have posted a question with multiple sub-parts, we will solve first three subparts for you. To get remaining sub-part solved please repost the complete question and mention the sub-parts to be solved.
From the provided information,
Mean (µ) = 1600
Standard deviation (σ) = 110
X~N (1600, 110)
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