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4)
circuit. On the same graph sketch the output Vout:
The graph below shows the input to the illustrated
0.01uF
Vin
Vaut
1
16kN
0.5
-0.5
-1
-0.002 -0.0015 -0.001 -0.0005
0.0005 0.001 0.0015 0.002
Time (s)
Voltage (V)

Expert Solution

Step 1

Given circuit,

Let , $V_{c}$ be the voltage through the capacitor,

Now the input voltage is always positive,

$- V_{i n} + V_{c} = 0 \Rightarrow V_{c} = V_{i n}$

For output voltage,

$- V_{i n} - V_{c} + V_{o u t} = 0 \Rightarrow V_{o u t} = V_{i n} + V_{c} = 2 V_{i n}$

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