The given system of differential equations are as follows. z'₁(t)= -6.2+1.1z₁ -0.8z2 13.8+2.1z₁-1.2z₂ , z₁(0) = 11, z₂(0) = 4 z'₂(t) = -

Advanced Engineering Mathematics
10th Edition
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Chapter2: Second-order Linear Odes
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solve the linear non-homogeneous system of equations with the given initial conditions.

The given system of differential equations is as follows:

\[ z'_1(t) = -6.2 + 1.1z_1 - 0.8z_2 \]

\[ z'_2(t) = -13.8 + 2.1z_1 - 1.2z_2 \]

with initial conditions \( z_1(0) = 11 \) and \( z_2(0) = 4 \).
Transcribed Image Text:The given system of differential equations is as follows: \[ z'_1(t) = -6.2 + 1.1z_1 - 0.8z_2 \] \[ z'_2(t) = -13.8 + 2.1z_1 - 1.2z_2 \] with initial conditions \( z_1(0) = 11 \) and \( z_2(0) = 4 \).
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