The given differential equation is already in standard form, as the coefficient of the highest order derivative is 1. W₁ = The next Wronskians to calculate use y₁ = ex and y₂ = e-2x that we identified from the complementary function and the function of x that makes the equation nonhomogeneous, f(x) = 6 + ex = W₂ = y" + 3y + 2y = = 0 Y2 0 e-2x (6 + ex)-1 -2e-2x Y₁ 0 6+ e* e-x 0 -ex (6 + e*)-1|
The given differential equation is already in standard form, as the coefficient of the highest order derivative is 1. W₁ = The next Wronskians to calculate use y₁ = ex and y₂ = e-2x that we identified from the complementary function and the function of x that makes the equation nonhomogeneous, f(x) = 6 + ex = W₂ = y" + 3y + 2y = = 0 Y2 0 e-2x (6 + ex)-1 -2e-2x Y₁ 0 6+ e* e-x 0 -ex (6 + e*)-1|
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![The given differential equation is already in standard form, as the coefficient of the highest order derivative is 1.
1
6 + e*
The next Wronskians to calculate use y₁ = ex and y₂ = e-2x that we identified from the complementary function and the function of x that makes the equation nonhomogeneous, f(x) =
6 + ex
W₁ =
W₂ =
y" + 3y' + 2y =
=
0 Y₂
f(x) y'₂
0
e-2x
(6 + ex)-1 -2e-2x
Y1 0
FOOD
Y₁' f(x)
|-0-X (6 + 0x)-1|](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0bd4fc6c-d3a4-4039-8062-71186c03b6c2%2F8db227a1-6da9-4e71-97ca-3d9f5abbbecb%2F6aw1agl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The given differential equation is already in standard form, as the coefficient of the highest order derivative is 1.
1
6 + e*
The next Wronskians to calculate use y₁ = ex and y₂ = e-2x that we identified from the complementary function and the function of x that makes the equation nonhomogeneous, f(x) =
6 + ex
W₁ =
W₂ =
y" + 3y' + 2y =
=
0 Y₂
f(x) y'₂
0
e-2x
(6 + ex)-1 -2e-2x
Y1 0
FOOD
Y₁' f(x)
|-0-X (6 + 0x)-1|
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