simplify the following equation using Boolean algebra. 1) X = A.B.C. Ó + A.B.C.D + A.B.C.D+A.B.C.D + A.B.C.D + A.B.C.D 1 + A.B.C.D + A.B.C.D + A.B.C.D + A.B.C.D +A.B.C.D. + A.B.C.D Ans : x = B.C + A-D + B. C + B. D

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1. X.0 = 0
3. X.X = X
5. X+0=X
7. X+X = X
9. X = X
X+YY+X
2. X.1=X
18. X+X.Y=X+Y
4. X.X = 0
6. X+1=1
10.
12. X+(Y+Z) = (X+Y) + Z
13. X.(Y.Z) = (X.Y).Z
14. X.(Y+Z) = X.Y + X.Z
15. X+(Y.Z) = (X + Y).(X + Z)
16. X+X.Y=X
8. X+X=1
11. X.YY.X
17.
X.(X+Y) = X
19. X.(X+Y)= X.Y
Transcribed Image Text:1. X.0 = 0 3. X.X = X 5. X+0=X 7. X+X = X 9. X = X X+YY+X 2. X.1=X 18. X+X.Y=X+Y 4. X.X = 0 6. X+1=1 10. 12. X+(Y+Z) = (X+Y) + Z 13. X.(Y.Z) = (X.Y).Z 14. X.(Y+Z) = X.Y + X.Z 15. X+(Y.Z) = (X + Y).(X + Z) 16. X+X.Y=X 8. X+X=1 11. X.YY.X 17. X.(X+Y) = X 19. X.(X+Y)= X.Y
simplify the following equation using Boolean algebra.
1) x = Á. B.C. Ō + A.B.C.D + A.B.C.D + A.B.C.D + A.B.C. D + A.B.C.D
+
· A.B.C.D + A.B.C.D + A.B.C.D + A.B.C.D +A.B.C.D + A.B.C.D
Ans : X = B.C + A - D + B . C + B. D
Transcribed Image Text:simplify the following equation using Boolean algebra. 1) x = Á. B.C. Ō + A.B.C.D + A.B.C.D + A.B.C.D + A.B.C. D + A.B.C.D + · A.B.C.D + A.B.C.D + A.B.C.D + A.B.C.D +A.B.C.D + A.B.C.D Ans : X = B.C + A - D + B . C + B. D
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May I know the origin of the values in the red circle?

The given Boolean expression
X = A.B.C.D + A. BCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD
+ ABCD + ABCD
2,3,4,5,6,9,10,11,12,13,14,15
X = A.B.C.D+ A. BCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD
+ ABCD + ABCD
X = A.B.C.D + A. BCD + ABCD + ABCD ABCD ABCD + ABCD + ABCD + ABCD + ABCD
+ ABCD + ABCD + ABCD
X = A.B.C.D + A. BCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ĀBCD + ABCD
+ ABCD + ABCD + ABCD
X = BC(A.D + A.D + AD + AD) + BD(AC + AC + AC + AC) + ABCD + AD(BC + BC + BC + BC)
X = BC(Ā. (D + D) + A(Ď + D)) + BD(Ñ(Ā + A) + C(Ā + A)) + ĀBĒD + AD(Ñ(B + B) + C(B
+ B))
Transcribed Image Text:The given Boolean expression X = A.B.C.D + A. BCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD 2,3,4,5,6,9,10,11,12,13,14,15 X = A.B.C.D+ A. BCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD X = A.B.C.D + A. BCD + ABCD + ABCD ABCD ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD X = A.B.C.D + A. BCD + ABCD + ABCD + ABCD + ABCD + ABCD + ABCD + ĀBCD + ABCD + ABCD + ABCD + ABCD X = BC(A.D + A.D + AD + AD) + BD(AC + AC + AC + AC) + ABCD + AD(BC + BC + BC + BC) X = BC(Ā. (D + D) + A(Ď + D)) + BD(Ñ(Ā + A) + C(Ā + A)) + ĀBĒD + AD(Ñ(B + B) + C(B + B))
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