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The general solution to the differential equation, y" (x) = 6x +1 is Oy=x³+²+₁x + C₂ Oy = x³ + + C₁ None of the other listed answers are correct. Oy = x³ + ² + x + 1

The general solution to the differential equation, y" (x) = 6x +1 is Oy=x³+²+₁x + C₂ Oy = x³ + + C₁ None of the other listed answers are correct. Oy = x³ + ² + x + 1

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Differential Equation Solution Selection** The general solution to the differential equation \( y''(x) = 6x + 1 \) is: - \( \circ \quad y = x^3 + \frac{x^2}{2} + C_1 x + C_2 \) - \( \circ \quad y = x^3 + \frac{x^2}{2} + C_1 \) - \( \circ \quad \text{None of the other listed answers are correct.} \) - \( \circ \quad y = x^3 + \frac{x^2}{2} + x + 1 \)
Transcribed Image Text:**Differential Equation Solution Selection** The general solution to the differential equation \( y''(x) = 6x + 1 \) is: - \( \circ \quad y = x^3 + \frac{x^2}{2} + C_1 x + C_2 \) - \( \circ \quad y = x^3 + \frac{x^2}{2} + C_1 \) - \( \circ \quad \text{None of the other listed answers are correct.} \) - \( \circ \quad y = x^3 + \frac{x^2}{2} + x + 1 \)
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