The general solution of the 1st-order ODE, (x + 3y − 2)y′ = e−3(x+3y−2)² – y − 1/3(x − 2) is Select one: O a. y(x) = ln(3x + C) − 2 ○ b._y(x) = [+ln(6x + C) + (2 − x)] /3 O Ⓒ c. y(x) = 3√3 [±ln(18(x + C)) + (2 − x)√3] O ○ d. y(x) = [½ln(6x + C) ± (2 − x)] /3
The general solution of the 1st-order ODE, (x + 3y − 2)y′ = e−3(x+3y−2)² – y − 1/3(x − 2) is Select one: O a. y(x) = ln(3x + C) − 2 ○ b._y(x) = [+ln(6x + C) + (2 − x)] /3 O Ⓒ c. y(x) = 3√3 [±ln(18(x + C)) + (2 − x)√3] O ○ d. y(x) = [½ln(6x + C) ± (2 − x)] /3
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![The general solution of the 1st-order ODE, (x + 3y − 2)y′ = e−³(x+3y−2)² – y − 1/3(x − 2) is
Select one:
O a. y(x) = ln(3x + C) − 2
O
○ b._y(x) = [+ln(6x + C) + (2 − x)] /3
Ⓒ c. y(x) = 3√3 [±ln(18(x + C)) + (2 − x)√3]
○ d. y(x) = [½ln(6x + C) ± (2 − x)] / 3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc86229f7-e5a9-4e38-b872-4fc8db453ef1%2Fe68b77d8-d283-4345-8755-87b9c2359636%2Fcvxlwmg_processed.png&w=3840&q=75)
Transcribed Image Text:The general solution of the 1st-order ODE, (x + 3y − 2)y′ = e−³(x+3y−2)² – y − 1/3(x − 2) is
Select one:
O a. y(x) = ln(3x + C) − 2
O
○ b._y(x) = [+ln(6x + C) + (2 − x)] /3
Ⓒ c. y(x) = 3√3 [±ln(18(x + C)) + (2 − x)√3]
○ d. y(x) = [½ln(6x + C) ± (2 − x)] / 3
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