The general solution of (D²+2D +1)(D²+4)y=0 is A y=(C,+Cx)e+C,cos2r + C ,sin2r B y=(C,+C,*)e*+C,cos2x + C ,sin2x © y=(C,+C,x)e*+C,e-2*+C,e2* D none of the given choices +C,
The general solution of (D²+2D +1)(D²+4)y=0 is A y=(C,+Cx)e+C,cos2r + C ,sin2r B y=(C,+C,*)e*+C,cos2x + C ,sin2x © y=(C,+C,x)e*+C,e-2*+C,e2* D none of the given choices +C,
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Question 5
The general solution of (D²+2D +1)(D²+4)y=0 is
A y=(C,+C,x)e*+C,cos2x + C ,sin2x
B
B y=(C,+Cx)e" +C,cos2x + C „sin2x
© »=(c,+Cx)e*+C,e-2"+Ce²*
D none of the given choices](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F729a6fc2-e951-4e2a-9e90-444394c8e37e%2F4a3d62da-1761-4719-a61a-38b379b1fad0%2Ff7ftrue_processed.png&w=3840&q=75)
Transcribed Image Text:Question 5
The general solution of (D²+2D +1)(D²+4)y=0 is
A y=(C,+C,x)e*+C,cos2x + C ,sin2x
B
B y=(C,+Cx)e" +C,cos2x + C „sin2x
© »=(c,+Cx)e*+C,e-2"+Ce²*
D none of the given choices
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