The general solution of (D³ +3D² +3D+1)y=0 a. y=C₁e¹ +C₂xе¹ + С₂x² e* c. y=C₁e¹ +C₂е¯* + С₂e¹ b. y Ce+C₂e +C₂e d. y=C₁e + C₂xе¯* + С₂x²e¯x

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The general solution of (D³ +3D² +3D+1)y=0
a. y=С₁e¹ +С₂xe* + С₂x² et
c. y=C₁e¹+C₂e¯*
+С₂е¹
b. y=C₁e +C₂е* +С₂е¯*
d. y=C₁e* +C₂xe* + С₂x²e¯*
Transcribed Image Text:The general solution of (D³ +3D² +3D+1)y=0 a. y=С₁e¹ +С₂xe* + С₂x² et c. y=C₁e¹+C₂e¯* +С₂е¹ b. y=C₁e +C₂е* +С₂е¯* d. y=C₁e* +C₂xe* + С₂x²e¯*
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