The general form of the element stiffness matrix system, with nodes indexed by i and j, is given as, - FO AE 1 L [47] {"; } = {FNG)(x) dx} + {N, (1)f(1) = N;(0) FO where F0 and f(1) denote boundary forces at positions x = 0 and x = 1, respectively. Form the two basis functions for element 2, and evaluate the right hand side vector of the matrix system 2 to form the local system of equations for element 2. Then use the local system for element 1 given by (3) 410-{2} -1] Ju₁) (2500- FO 2500 ¹ to form and solve the global system of equations for u₁, u₂ and u3. AE 1 L

Elements Of Electromagnetics
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The general form of the element stiffness matrix system, with nodes indexed by i and j, is given
as,
AE
1
4[47] {u} =
L
S; N¡(x)l(x)dx \ __ [N;(1)ƒ(1) – N;(0) FO
N₁(x)l(x)dx] [N₂(1)ƒ(1) – N₂(0) Fo]'
+
(2)
Xi
0 and x = 1, respectively. Form the
where F0 and f(1) denote boundary forces at positions x =
two basis functions for element 2, and evaluate the right hand side vector of the matrix system
2 to form the local system of equations for element 2. Then use the local system for element 1
given by
AE
U
4€ [11] {2}={
L
U2
to form and solve the global system of equations for u₁, u2₂ and u3.
2500 - FO
2500
FO}
(3)
Transcribed Image Text:The general form of the element stiffness matrix system, with nodes indexed by i and j, is given as, AE 1 4[47] {u} = L S; N¡(x)l(x)dx \ __ [N;(1)ƒ(1) – N;(0) FO N₁(x)l(x)dx] [N₂(1)ƒ(1) – N₂(0) Fo]' + (2) Xi 0 and x = 1, respectively. Form the where F0 and f(1) denote boundary forces at positions x = two basis functions for element 2, and evaluate the right hand side vector of the matrix system 2 to form the local system of equations for element 2. Then use the local system for element 1 given by AE U 4€ [11] {2}={ L U2 to form and solve the global system of equations for u₁, u2₂ and u3. 2500 - FO 2500 FO} (3)
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