The general equation for a circle is a(x? + y*) + bx + cy + d = 0. There is exactly one circle passing through the points (2, –1), (–2, 3), and (0, 0). Find an equation for this circle. (x² + y²) + Y + = 0

Q: Write the standard equation of a circle that has the end points of one of its diameters at (1,5) and…

A:

Q: 6. Write the standard form of the equation of a circle with the given center at (5,7) and a (5)² +…

A: Centre= (5,7) Radius= 2

Q: Find the standard form of the equation of the circle with a diameter having two points (1, -6) & (7,…

A: The end points of diameter of the circle are (1,-6)  and (7,2). The standard form of equation of…

Q: For the equation of the circle (x-10)2+(y+2)2=34 Please explain why the point (5,1) is on the…

A:

Q: 2.Express the equation in standard form and indicate the center and radius, if a circle exists. a.…

A: Part a,Given,            x2+y2-10x-14y-7=0We know that,          The general equation of the circle…

Q: Draw a circle with an equation of x2+4x+y2−4y=1.

A: Given,