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The gate in Fig. 3-50a (shown in raised position) weig gravity is 1.5 ft from the left face and 2.0 ft above the does the gate just begin to swing up (rotate counterclo Ro 2 S0h ond eoncider 1 ft

The gate in Fig. 3-50a (shown in raised position) weig gravity is 1.5 ft from the left face and 2.0 ft above the does the gate just begin to swing up (rotate counterclo Ro 2 S0h ond eoncider 1 ft

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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9:06 A researchgate.net 3.61 The gate in Fig. 3-50a (shown in raised position) weigi gravity is 1.5 ft from the left face and 2.0 ft above the does the gate just begin to swing up (rotate counterclo I Refer to Fig. 3-50b and consider 1 ft of length. F = (2)(350) – (5 – ho/3)(31.2h%) =0, ho=2.30 ft. Water 5 ft Fig. 3-50(a) 76 O CHAPTER 3 For the gate described in Prob. 3.61 and Fig. 3- shown in Fig. 3-50a. 3.62 I See Fig. 3-51. F = yhA = (62.4)(h)[(5)(1)] = (1.5)(350) + (h/3)(31.2h²) – (2.5)(312h) = 0, h
Transcribed Image Text:9:06 A researchgate.net 3.61 The gate in Fig. 3-50a (shown in raised position) weigi gravity is 1.5 ft from the left face and 2.0 ft above the does the gate just begin to swing up (rotate counterclo I Refer to Fig. 3-50b and consider 1 ft of length. F = (2)(350) – (5 – ho/3)(31.2h%) =0, ho=2.30 ft. Water 5 ft Fig. 3-50(a) 76 O CHAPTER 3 For the gate described in Prob. 3.61 and Fig. 3- shown in Fig. 3-50a. 3.62 I See Fig. 3-51. F = yhA = (62.4)(h)[(5)(1)] = (1.5)(350) + (h/3)(31.2h²) – (2.5)(312h) = 0, h
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