The gas in a 250.0 mL piston experiences a change in pressure from 1.00 atm to 2.60 atm. What is the new volume (in mL) assuming the moles of gas and temperature are held constant?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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### Question 8 of 14

The gas in a 250.0 mL piston experiences a change in pressure from 1.00 atm to 2.60 atm. What is the new volume (in mL) assuming the moles of gas and temperature are held constant?

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### Explanation:

This question applies Boyle's Law, which states that the pressure of a gas times its volume is a constant when the temperature and the amount of gas remain unchanged. Mathematically, this is expressed as:

\[ P_1 \times V_1 = P_2 \times V_2 \]

Where:
- \( P_1 \) is the initial pressure (1.00 atm)
- \( V_1 \) is the initial volume (250.0 mL)
- \( P_2 \) is the final pressure (2.60 atm)
- \( V_2 \) is the final volume, which we need to find.

### Interface Elements:

- A calculator interface is provided with numbers, decimal point, and operations, allowing the user to compute the answer, possibly as part of an interactive exercise.
Transcribed Image Text:### Question 8 of 14 The gas in a 250.0 mL piston experiences a change in pressure from 1.00 atm to 2.60 atm. What is the new volume (in mL) assuming the moles of gas and temperature are held constant? --- ### Explanation: This question applies Boyle's Law, which states that the pressure of a gas times its volume is a constant when the temperature and the amount of gas remain unchanged. Mathematically, this is expressed as: \[ P_1 \times V_1 = P_2 \times V_2 \] Where: - \( P_1 \) is the initial pressure (1.00 atm) - \( V_1 \) is the initial volume (250.0 mL) - \( P_2 \) is the final pressure (2.60 atm) - \( V_2 \) is the final volume, which we need to find. ### Interface Elements: - A calculator interface is provided with numbers, decimal point, and operations, allowing the user to compute the answer, possibly as part of an interactive exercise.
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