The gas equation for one mole of oxygen relates its pressure, P (in atmospheres), its temperature, T (in K), and its volume, V (in cubic decimeters, dm³): 1 0.52754. - 0.3879 P + 12.187 V P. V2 T = 16.574. dT= 1 V (a) Find the temperature T and differential dT if the volume is 22 dm³ and the pressure is 1.5 atmosphere. T = 9. (b) Use your answer to part (a) to estimate how much the pressure would have to change if the volume increased by 1.5 dm³ and the temperature remained constant. change in pressure =

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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The gas equation for one mole of oxygen relates its pressure, P (in atmospheres), its temperature, T (in K), and its volume, V (in cubic decimeters, dm³):
1
0.52754. - 0.3879 P + 12.187 V P.
V2
T = 16.574.
dT=
1
V
(a) Find the temperature T and differential dT if the volume is 22 dm³ and the pressure is 1.5 atmosphere.
T =
9.
(b) Use your answer to part (a) to estimate how much the pressure would have to change if the volume increased by 1.5 dm³ and the temperature remained constant.
change in pressure =
Transcribed Image Text:The gas equation for one mole of oxygen relates its pressure, P (in atmospheres), its temperature, T (in K), and its volume, V (in cubic decimeters, dm³): 1 0.52754. - 0.3879 P + 12.187 V P. V2 T = 16.574. dT= 1 V (a) Find the temperature T and differential dT if the volume is 22 dm³ and the pressure is 1.5 atmosphere. T = 9. (b) Use your answer to part (a) to estimate how much the pressure would have to change if the volume increased by 1.5 dm³ and the temperature remained constant. change in pressure =
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