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The gas equation for one mole of oxygen relates its pressure, P (in atmospheres), its temperature, T (in K), and its volume, V (in cubic decimeters, dm³ ): 1 1 0.52754· V T = 16.574 · 0.3879 P+ 12.187 V P. V2 (a) Find the temperature T and differential dT if the volume is 28 dm and the pressure is 1.5 atmosphere. T = dT = (b) Use your answer to part (a) to estimate how much the volume would have to change if the pressure increased by 0.05 atmosphere and the temperature remained constant. change in volume =

The gas equation for one mole of oxygen relates its pressure, P (in atmospheres), its temperature, T (in K), and its volume, V (in cubic decimeters, dm³ ): 1 1 0.52754· V T = 16.574 · 0.3879 P+ 12.187 V P. V2 (a) Find the temperature T and differential dT if the volume is 28 dm and the pressure is 1.5 atmosphere. T = dT = (b) Use your answer to part (a) to estimate how much the volume would have to change if the pressure increased by 0.05 atmosphere and the temperature remained constant. change in volume =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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11.4: Problem 9 Previous Problem Problem List Next Problem The gas equation for one mole of oxygen relates its pressure, P (in atmospheres), its temperature, T (in K), and its volume, V (in cubic decimeters, dm³): 1 0.52754 · V T = 16.574 · 0.3879 P+ 12.187 V P. - V2 (a) Find the temperature T and differential dT if the volume is 28 dm and the pressure is 1.5 atmosphere. T = dT = (b) Use your answer to part (a) to estimate how much the volume would have to change if the pressure increased by 0.05 atmosphere and the temperature remained constant. change in volume =
Transcribed Image Text:11.4: Problem 9 Previous Problem Problem List Next Problem The gas equation for one mole of oxygen relates its pressure, P (in atmospheres), its temperature, T (in K), and its volume, V (in cubic decimeters, dm³): 1 0.52754 · V T = 16.574 · 0.3879 P+ 12.187 V P. - V2 (a) Find the temperature T and differential dT if the volume is 28 dm and the pressure is 1.5 atmosphere. T = dT = (b) Use your answer to part (a) to estimate how much the volume would have to change if the pressure increased by 0.05 atmosphere and the temperature remained constant. change in volume =
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