The function y = 15x | is tangent at two points to a circle of radius 4 centred on the positive y- == axis. Find the area bounded by the two curves. (Click on the graph for a larger version.) To begin, you will need to find the centre of the circle (0, k) and the points of tangency x = ±a, a > 0, where a = k= Show Hints below. If you need a hint on how to find these, click on Next, you can use symmetry of the situation to set up an integral which represents the area of the shaded region: a 2 ford f(x) dx where f(x) = To evaluate this integral you will need to use a trigonometric substitution, let x = And finally you will work down to finding: Area = (use there instead of square units.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The function y = 15x | is tangent at two points to a circle of radius 4 centred on the positive y-
==
axis. Find the area bounded by the two curves.
(Click on the graph for a larger version.)
To begin, you will need to find the centre of the circle (0, k) and the points of tangency
x = ±a, a > 0, where
a =
k=
Show Hints below.
If you need a hint on how to find these, click on
Next, you can use symmetry of the situation to set up an integral which represents the area of
the shaded region:
a
2 ford
f(x) dx
where f(x) =
To evaluate this integral you will need to use a trigonometric substitution, let x =
And finally you will work down to finding:
Area =
(use there instead of
square units.
Transcribed Image Text:The function y = 15x | is tangent at two points to a circle of radius 4 centred on the positive y- == axis. Find the area bounded by the two curves. (Click on the graph for a larger version.) To begin, you will need to find the centre of the circle (0, k) and the points of tangency x = ±a, a > 0, where a = k= Show Hints below. If you need a hint on how to find these, click on Next, you can use symmetry of the situation to set up an integral which represents the area of the shaded region: a 2 ford f(x) dx where f(x) = To evaluate this integral you will need to use a trigonometric substitution, let x = And finally you will work down to finding: Area = (use there instead of square units.
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