The function P(x) = - 1.75a? + 1250x – 9000 gives %3D - the profit when x units of a certain product are sold. Find

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Quadratic Function and Profit Analysis

The function \( P(x) = -1.75x^2 + 1250x - 9000 \) gives the profit when \( x \) units of a certain product are sold. Analyze this function to understand the relationship between the number of units sold and the profit generated.

#### Components of the Function:
- **Quadratic term** (\(-1.75x^2\)): Indicates that the profit function is a downward-opening parabola. The coefficient is negative, implying that there is a maximum profit point.
- **Linear term** (\(1250x\)): Contributes to the increase in profit as more units are sold.
- **Constant term** (\(-9000\)): Represents the fixed costs or initial losses when no units are sold.

#### Tasks:
1. **Identify the Maximum Profit Point**: Determine the number of units \( x \) that should be sold to achieve maximum profit.
2. **Profit Calculation**: Calculate the profit for given values of \( x \).

This function enables businesses to predict and optimize their profit based on the number of units sold. Understanding this relation helps in making strategic decisions regarding production and sales.
Transcribed Image Text:### Quadratic Function and Profit Analysis The function \( P(x) = -1.75x^2 + 1250x - 9000 \) gives the profit when \( x \) units of a certain product are sold. Analyze this function to understand the relationship between the number of units sold and the profit generated. #### Components of the Function: - **Quadratic term** (\(-1.75x^2\)): Indicates that the profit function is a downward-opening parabola. The coefficient is negative, implying that there is a maximum profit point. - **Linear term** (\(1250x\)): Contributes to the increase in profit as more units are sold. - **Constant term** (\(-9000\)): Represents the fixed costs or initial losses when no units are sold. #### Tasks: 1. **Identify the Maximum Profit Point**: Determine the number of units \( x \) that should be sold to achieve maximum profit. 2. **Profit Calculation**: Calculate the profit for given values of \( x \). This function enables businesses to predict and optimize their profit based on the number of units sold. Understanding this relation helps in making strategic decisions regarding production and sales.
### Understanding Profit Changes and Sales Units

#### Economic Concepts and Calculations

In this section, we will explore some fundamental concepts related to profit changes and unit sales. Pay close attention to the following tasks and how to approach them:

#### Part d: Rate of Change in Profit
To determine the rate at which profit changes on average as the number of units sold increases, consider this specific scenario:

- The number of units sold rises from 90 to 180 units.

The question asks for the average rate of change in profit per unit increase. Use the formula for the average rate of change:

\[ \text{Average Rate of Change} = \frac{\Delta \text{Profit}}{{\Delta \text{Quantity}}} \]

where:
- \(\Delta \text{Profit}\) is the change in profit.
- \(\Delta \text{Quantity}\) is the change in the number of units sold (which in this case is from 90 to 180 units).

You need to enter the calculated value in the following box:

\[ \boxed{\phantom{0}} \ \text{dollars per unit} \]

#### Part e: Number of Units for Profit Maximization
This part requires identifying the number of units sold at the point where the profit stops increasing and begins to decrease. This typically involves finding:

- The maximum profit point, which may require calculus (finding the derivative of the profit function and setting it to zero) or analyzing given profit data.

If necessary, round your final answer to the nearest whole number. Enter this value in the designated box:

\[ \boxed{\phantom{0}} \ \text{units} \]

By following these steps and practicing with real data or hypothetical profit functions, students can gain a deeper understanding of economic and math principles related to business and sales optimization.
Transcribed Image Text:### Understanding Profit Changes and Sales Units #### Economic Concepts and Calculations In this section, we will explore some fundamental concepts related to profit changes and unit sales. Pay close attention to the following tasks and how to approach them: #### Part d: Rate of Change in Profit To determine the rate at which profit changes on average as the number of units sold increases, consider this specific scenario: - The number of units sold rises from 90 to 180 units. The question asks for the average rate of change in profit per unit increase. Use the formula for the average rate of change: \[ \text{Average Rate of Change} = \frac{\Delta \text{Profit}}{{\Delta \text{Quantity}}} \] where: - \(\Delta \text{Profit}\) is the change in profit. - \(\Delta \text{Quantity}\) is the change in the number of units sold (which in this case is from 90 to 180 units). You need to enter the calculated value in the following box: \[ \boxed{\phantom{0}} \ \text{dollars per unit} \] #### Part e: Number of Units for Profit Maximization This part requires identifying the number of units sold at the point where the profit stops increasing and begins to decrease. This typically involves finding: - The maximum profit point, which may require calculus (finding the derivative of the profit function and setting it to zero) or analyzing given profit data. If necessary, round your final answer to the nearest whole number. Enter this value in the designated box: \[ \boxed{\phantom{0}} \ \text{units} \] By following these steps and practicing with real data or hypothetical profit functions, students can gain a deeper understanding of economic and math principles related to business and sales optimization.
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