The function is given piecewise: f(x) = = et 0 tan(x) Is function continuous at x = 0? Explain. if x < 0 if x = 0 if x > 0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
icon
Related questions
Question
### Piecewise Function and Continuity

**Problem Statement:**

The function is given piecewise as follows:

\[
f(x) =
\begin{cases} 
e^x & \text{if } x < 0 \\
0 & \text{if } x = 0 \\
\tan(x) & \text{if } x > 0 
\end{cases}
\]

**Question:**
Is the function continuous at \( x = 0 \)? Explain.

**Solution:**
To determine if the function is continuous at \( x = 0 \), we need to check the following three conditions of continuity at a point \( c \):

1. \( f(c) \) is defined.
2. The limit of \( f(x) \) as \( x \) approaches \( c \) exists.
3. The limit of \( f(x) \) as \( x \) approaches \( c \) is equal to \( f(c) \).

Let's check each of these conditions for \( c = 0 \):

1. **Is \( f(0) \) defined?**
   Yes, \( f(0) = 0 \).

2. **Does \( \lim_{x \to 0} f(x) \) exist?**
   We need to check the left-hand limit and the right-hand limit:
   
   - **Left-hand limit:**
     \[
     \lim_{x \to 0^-} f(x) = \lim_{x \to 0^-} e^x = e^0 = 1 
     \]

   - **Right-hand limit:**
     \[
     \lim_{x \to 0^+} f(x) = \lim_{x \to 0^+} \tan(x)
     \]
     The limit of \( \tan(x) \) as \( x \) approaches 0 from the right is 0.

   Since the left-hand limit and the right-hand limit are not equal (1 versus 0), the limit of \( f(x) \) as \( x \) approaches 0 does not exist.

3. **Is \( \lim_{x \to 0} f(x) = f(0) \)?**
   Since the limit does not exist, this condition is not satisfied.

Therefore, the function \( f(x) \) is **not continuous** at \( x
Transcribed Image Text:### Piecewise Function and Continuity **Problem Statement:** The function is given piecewise as follows: \[ f(x) = \begin{cases} e^x & \text{if } x < 0 \\ 0 & \text{if } x = 0 \\ \tan(x) & \text{if } x > 0 \end{cases} \] **Question:** Is the function continuous at \( x = 0 \)? Explain. **Solution:** To determine if the function is continuous at \( x = 0 \), we need to check the following three conditions of continuity at a point \( c \): 1. \( f(c) \) is defined. 2. The limit of \( f(x) \) as \( x \) approaches \( c \) exists. 3. The limit of \( f(x) \) as \( x \) approaches \( c \) is equal to \( f(c) \). Let's check each of these conditions for \( c = 0 \): 1. **Is \( f(0) \) defined?** Yes, \( f(0) = 0 \). 2. **Does \( \lim_{x \to 0} f(x) \) exist?** We need to check the left-hand limit and the right-hand limit: - **Left-hand limit:** \[ \lim_{x \to 0^-} f(x) = \lim_{x \to 0^-} e^x = e^0 = 1 \] - **Right-hand limit:** \[ \lim_{x \to 0^+} f(x) = \lim_{x \to 0^+} \tan(x) \] The limit of \( \tan(x) \) as \( x \) approaches 0 from the right is 0. Since the left-hand limit and the right-hand limit are not equal (1 versus 0), the limit of \( f(x) \) as \( x \) approaches 0 does not exist. 3. **Is \( \lim_{x \to 0} f(x) = f(0) \)?** Since the limit does not exist, this condition is not satisfied. Therefore, the function \( f(x) \) is **not continuous** at \( x
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning