The function f(t) satisfies the ODE and the intial conditions f(0) = −5, d² dt2 -(0)=3. F(s)= | df f(t)-4 - 4 (dƒ(t)) - -5 f(t)=9t² +5t-5 Enter the laplace transfrom F (s) of f(t) below in Maple syntax. Note: You do not need to simplify the expression for F(s) or resolve it to partial fractions. & P
The function f(t) satisfies the ODE and the intial conditions f(0) = −5, d² dt2 -(0)=3. F(s)= | df f(t)-4 - 4 (dƒ(t)) - -5 f(t)=9t² +5t-5 Enter the laplace transfrom F (s) of f(t) below in Maple syntax. Note: You do not need to simplify the expression for F(s) or resolve it to partial fractions. & P
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:We can apply Laplace transform to an ODE in t with given initial values to form an algebraic equation in F(s) the Laplace transform of
the solution. Then we solve the equation to get the Laplace transform of the solution. Finally, we apply the inverse Laplace transform to
get the solution of the IVP.
This question is on the first half of the process.
The function f(t) satisfies the ODE
and the intial conditions f(0) = -5,
d²
dt²
-(0)=3.
df
dt
_4(&f())_
f(t)- 4
-5 f(t)=9t²+5t-5
Enter the laplace transfrom F (s) of f(t) below in Maple syntax.
Note: You do not need to simplify the expression for F(s) or resolve it to partial fractions.
F (s)-|
& P
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