The function f (x) called invariant under differentiation operator function (IUDO. function) if: f'(x) = f(x).Show that: if u(x) = -2cosh(x) and v(x) = -sinh(x) + cosh(x) then both of u(x) and v(x) is not IUDO. function but h(x) = u(x) + v(x) is IUDO. function

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