The function f is given by f(x) = ½e-2x 1. What is the equation of the line tangent to the graph of f when x = ln 3? Answer Oy+=(x - In 3) ○ y + 1 = −(x - ln 3) 18 - Oy+ 1 = -10 (x – ln 3) Oy+=-10 (x – ln 3)

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A:

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A: Solution:-

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A:

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