The function 'CountWords' is given below to find the number of words in a sentence. Which of the following is the missing code line? int CountWords(char *P) (int count%3D0,words-D0,i; while(P[count]I='\0') count++;for (i=0;i<=count;i++) { words++; } return words; } ............ a. if ((P[i]F=" :&&P[i]I=' ')||P[i]=="\0") b. if ((P[i+1]==' '&&P[i+1]l=' ')||P[i)=='\0') c. if ((P[i+1]==' '&&P[i]!=' ')||P[i+1]=="\0") d. if ((P[i]==' '&8&P[i+1]l=' ')||P[i]=="\0')
The function 'CountWords' is given below to find the number of words in a sentence. Which of the following is the missing code line? int CountWords(char *P) (int count%3D0,words-D0,i; while(P[count]I='\0') count++;for (i=0;i<=count;i++) { words++; } return words; } ............ a. if ((P[i]F=" :&&P[i]I=' ')||P[i]=="\0") b. if ((P[i+1]==' '&&P[i+1]l=' ')||P[i)=='\0') c. if ((P[i+1]==' '&&P[i]!=' ')||P[i+1]=="\0") d. if ((P[i]==' '&8&P[i+1]l=' ')||P[i]=="\0')
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![The function 'CountWords' is given below to find the number of words in a sentence. Which of
the following is the missing code line?
int CountWords(char *P) (int count%3D0,words-D0,i; while(P[count]I='\0') count++;for
(i=0;i<=count;i++) {
words++; } return words; }
............
a. if ((P[i]F=" :&&P[i]I=' ')||P[i]=="\0")
b. if ((P[i+1]==' '&&P[i+1]l=' ')||P[i)=='\0')
c. if ((P[i+1]==' '&&P[i]!=' ')||P[i+1]=="\0")
d. if ((P[i]==' '&8&P[i+1]l=' ')||P[i]=="\0')](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd161d2b7-04cf-46ac-b6fd-45651d1bcb10%2Fa36b8418-8f33-4334-88c7-513586d0e362%2F02tq3y.png&w=3840&q=75)
Transcribed Image Text:The function 'CountWords' is given below to find the number of words in a sentence. Which of
the following is the missing code line?
int CountWords(char *P) (int count%3D0,words-D0,i; while(P[count]I='\0') count++;for
(i=0;i<=count;i++) {
words++; } return words; }
............
a. if ((P[i]F=" :&&P[i]I=' ')||P[i]=="\0")
b. if ((P[i+1]==' '&&P[i+1]l=' ')||P[i)=='\0')
c. if ((P[i+1]==' '&&P[i]!=' ')||P[i+1]=="\0")
d. if ((P[i]==' '&8&P[i+1]l=' ')||P[i]=="\0')
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