The function C (t) = 100000 + 3000t models the monthly cost for Toyota to manufacture its Corolla at the Mississippi plant. A new Corolla sells for $20,000. What is the minimum number o cars Toyota must sell in order to make a profit? Type in a single number as your answer. Question 2 Following from question 1, what is the integral expression that represents the area between the curves on the interval [0,10]? 5.882 10 LSs [(100000 + 3000r) – (200001)] dt + [ [(200001) – (100000 + 30001)] dt 10 L" [(100000 + 3000r) – (20000r)] dt 10 S" [(200001) – (100000 + 3000)] dt 5.882 (20000r) – (100000 + 30001)] dt + S, [(100000 + 30001) – (20000r)] dt 10 5.882

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Question 1

The function \( C(t) = 100000 + 3000t \) models the monthly cost for Toyota to manufacture its Corolla at the Mississippi plant. A new Corolla sells for $20,000. What is the minimum number of cars Toyota must sell in order to make a profit?

Type in a single number as your answer.

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Question 2

Following from question 1, what is the integral expression that represents the area between the curves on the interval \([0,10]\)?

- \( \int_{0}^{5.882} [(100000 + 3000t) - (20000t)] \, dt + \int_{5.882}^{10} [(20000t) - (100000 + 3000t)] \, dt \)

- \( \int_{0}^{10} [(100000 + 3000t) - (20000t)] \, dt \)

- \( \int_{0}^{10} [(20000t) - (100000 + 3000t)] \, dt \)

- \( \int_{0}^{5.882} [(20000t) - (100000 + 3000t)] \, dt + \int_{5.882}^{10} [(100000 + 3000t) - (20000t)] \, dt \)
Transcribed Image Text:Question 1 The function \( C(t) = 100000 + 3000t \) models the monthly cost for Toyota to manufacture its Corolla at the Mississippi plant. A new Corolla sells for $20,000. What is the minimum number of cars Toyota must sell in order to make a profit? Type in a single number as your answer. [Input Box] Question 2 Following from question 1, what is the integral expression that represents the area between the curves on the interval \([0,10]\)? - \( \int_{0}^{5.882} [(100000 + 3000t) - (20000t)] \, dt + \int_{5.882}^{10} [(20000t) - (100000 + 3000t)] \, dt \) - \( \int_{0}^{10} [(100000 + 3000t) - (20000t)] \, dt \) - \( \int_{0}^{10} [(20000t) - (100000 + 3000t)] \, dt \) - \( \int_{0}^{5.882} [(20000t) - (100000 + 3000t)] \, dt + \int_{5.882}^{10} [(100000 + 3000t) - (20000t)] \, dt \)
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