Answer wyickly The function below is supposed to replicate the lower() string method (that is, it converts alluppercase letters to lowercase, and doesn't change any other characters).def lower (word):out =for ch in word:IIif ord('A') <= ord (ch) <= ord ('Z'):new_ch = chr(_out += new_chelse:out += chreturn outFill in the blank such that the function works as intended.Hint: The ascii value for a lowercase letter is always 32 higher than the ascii value for itsuppercase version. For example, ord('A') is 65, and ord('a') is 97.

Answered: The function below is supposed to…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Answer wyickly

The function below is supposed to replicate the lower() string method (that is, it converts all
uppercase letters to lowercase, and doesn't change any other characters).
def lower (word):
out =
for ch in word:
II
if ord('A') <= ord (ch) <= ord ('Z'):
new_ch = chr(_
out += new_ch
else:
out += ch
return out
Fill in the blank such that the function works as intended.
Hint: The ascii value for a lowercase letter is always 32 higher than the ascii value for its
uppercase version. For example, ord('A') is 65, and ord('a') is 97.

Expert Solution

Step 1

chr function returns the character corresponding to a Unicode code integer. Thus, the input to chr function must be the Unicode for the lowercase characters.

The Unicode for the lowercase characters is 32 higher than the ASCII value for its uppercase version.
Thus, add 32 to the ord(ch) of the Uppercase letter and give it as input to the chr function.

Therefore, the blank can be filled as follows:

new_ch = chr(ord(ch) + 32)

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