The function3y = -x³ (2x – 3) (4x + 3)° is negativeon the intervalsO a) x € (-∞, –) and x4E (0, ∞)O b) x € (-∞, – ) and x4€ (클, 0)Odx€ (-. 0) and x e (, 00)43d) x E (-∞, -) and x4X3E (0, )3

The given function is: y=-x3(2x-3)(4x+3)3

The function 3 y = -x³ (2x – 3)(4x + 3)° is negative on the intervals ) a) x E (-∞, –) and x 4 X 3 E (0, 0) O b) x € (-0∞, –) and x 4 € (글, 0) OdxE (-1, 0) and x € (금, 0) 4 3 OdxE (-8, -를) and x E (0, ) X 3 3

The function 3 y = -x³ (2x – 3)(4x + 3)° is negative on the intervals ) a) x E (-∞, –) and x 4 X 3 E (0, 0) O b) x € (-0∞, –) and x 4 € (글, 0) OdxE (-1, 0) and x € (금, 0) 4 3 OdxE (-8, -를) and x E (0, ) X 3 3

Trigonometry (11th Edition)

11th Edition

ISBN:9780134217437

Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Chapter1: Trigonometric Functions

Section: Chapter Questions

Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.

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