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The frequency of this wave is...

The frequency of this wave is...

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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**Oscilloscope Waveform Analysis** *Diagram Description:* The diagram displays a sinusoidal waveform on a grid, typical of an oscilloscope reading. Each square on the grid represents both a specific voltage and time interval, as defined by the settings on the oscilloscope. - **Vertical axis (Voltage):** Each division on the vertical axis is set to 0.2 V/div. - **Horizontal axis (Time):** Each division on the horizontal axis is set to 2 microseconds/div. *Question:* The objective is to determine the frequency of the wave depicted. *Options:* - 125 kHz - 4 microseconds - 4 Hz - 1.25 MHz - 2.5 MHz To calculate the frequency, observe the number of divisions per cycle on the time axis and apply the formula: \[ \text{Frequency} = \frac{1}{\text{Period}} \] *Period Calculation:* The period is the time it takes for one complete cycle. Count the number of divisions for one complete wave cycle, then multiply by the time/div setting. Use this period to determine the frequency.
Transcribed Image Text:**Oscilloscope Waveform Analysis** *Diagram Description:* The diagram displays a sinusoidal waveform on a grid, typical of an oscilloscope reading. Each square on the grid represents both a specific voltage and time interval, as defined by the settings on the oscilloscope. - **Vertical axis (Voltage):** Each division on the vertical axis is set to 0.2 V/div. - **Horizontal axis (Time):** Each division on the horizontal axis is set to 2 microseconds/div. *Question:* The objective is to determine the frequency of the wave depicted. *Options:* - 125 kHz - 4 microseconds - 4 Hz - 1.25 MHz - 2.5 MHz To calculate the frequency, observe the number of divisions per cycle on the time axis and apply the formula: \[ \text{Frequency} = \frac{1}{\text{Period}} \] *Period Calculation:* The period is the time it takes for one complete cycle. Count the number of divisions for one complete wave cycle, then multiply by the time/div setting. Use this period to determine the frequency.
**Transcription:** This question references the diagram above. To display this on the oscilloscope, the volts/div knob is set to 0.2 V/div and the time/div knob is set to 2 microseconds/div. The amplitude of this wave is... - ○ 0.4 Volts - ○ 4 microseconds - ○ 0.8 Volts - ○ 2 microseconds **Description of Diagram:** The diagram shows a sinusoidal wave displayed on an oscilloscope grid. The grid consists of vertical and horizontal lines that form square divisions. The wave oscillates symmetrically above and below the center horizontal axis across several divisions. - The vertical scale of the oscilloscope is set to 0.2 V per division. - The horizontal scale (time) is set to 2 microseconds per division. By measuring the peak of the wave: - The wave extends 2 divisions above the center line, leading to an amplitude calculation of 0.4 Volts (2 divisions x 0.2 V/div).
Transcribed Image Text:**Transcription:** This question references the diagram above. To display this on the oscilloscope, the volts/div knob is set to 0.2 V/div and the time/div knob is set to 2 microseconds/div. The amplitude of this wave is... - ○ 0.4 Volts - ○ 4 microseconds - ○ 0.8 Volts - ○ 2 microseconds **Description of Diagram:** The diagram shows a sinusoidal wave displayed on an oscilloscope grid. The grid consists of vertical and horizontal lines that form square divisions. The wave oscillates symmetrically above and below the center horizontal axis across several divisions. - The vertical scale of the oscilloscope is set to 0.2 V per division. - The horizontal scale (time) is set to 2 microseconds per division. By measuring the peak of the wave: - The wave extends 2 divisions above the center line, leading to an amplitude calculation of 0.4 Volts (2 divisions x 0.2 V/div).
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