The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean μ=$1.519 and standard deviation σ=$0.965 The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Comparethese results to the actual mean u = $1.519 and standard deviation o =$0.965.Click the icon to view the frequency distribution for the tax rates.Frequency distribution of cigarette tax ratesThe population mean is $Таx RateFrequency(Round to three decimal places as needed.)0.00–0.490.50-0.9915The population standard deviation is $1.00–1.497(Round to three decimal places as needed.)1.50–1.992.00–2.49Compare these results to the values found using the actual data.2.50–2.9943.00–3.494A. The grouped mean is slightly smaller, while the grouped standard deviation is slightly larger.3.50–3.991B. The grouped mean is slightly larger, while the grouped standard deviation is slightly smaller.4.00–4.491C. The grouped values are both slightly larger.D. The grouped values are both slightly smaller.PrintDone

Frequency distribution of cigarettes tax rate. We have to find out population mean and population…

The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean u= $1.519 and standard deviation o = $0.965. E Click the icon to view the frequency distribution for the tax rates. - X Frequency distribution of cigarette tax rates The population mean is $. Tax Rate Frequency P (Round to three decimal places as needed.) 0.00-0.49 0.50-0.99 15 The population standard deviation is $. 1.00–1.49 7 (Round to three decimal places as needed.) 1.50-1.99 6 2.00-2.49 Compare these results to the values found using the actual data. 2.50-2.99 4 3.00-3.49 4 O A. The grouped mean is slightly smaller, while the grouped standard deviation is slightly larger. 3.50-3.99 1 O B. The grouped mean is slightly larger, while the grouped standard deviation is slightly smaller. 4.00-4.49 1 O C. The grouped values are both slightly larger. O D. The grouped values are both slightly smaller. Print Done

The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean u= $1.519 and standard deviation o = $0.965. E Click the icon to view the frequency distribution for the tax rates. - X Frequency distribution of cigarette tax rates The population mean is $. Tax Rate Frequency P (Round to three decimal places as needed.) 0.00-0.49 0.50-0.99 15 The population standard deviation is $. 1.00–1.49 7 (Round to three decimal places as needed.) 1.50-1.99 6 2.00-2.49 Compare these results to the values found using the actual data. 2.50-2.99 4 3.00-3.49 4 O A. The grouped mean is slightly smaller, while the grouped standard deviation is slightly larger. 3.50-3.99 1 O B. The grouped mean is slightly larger, while the grouped standard deviation is slightly smaller. 4.00-4.49 1 O C. The grouped values are both slightly larger. O D. The grouped values are both slightly smaller. Print Done

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 33 and the age of the winner for best actress was 47. For all best actors, the mean age is 44.4 years and the standard deviation is 6.5 years. For all best actresses, the mean age is 32.8 years and the standard deviation is 11.2 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z= and the z score for the actress is z = the V had the more extreme age. (Round to two decimal places.)
Rachael got a 660 on the analytical portion of the Graduate Record Exam (GRE). If GRE scores are normally distributed and have mean μ = 600 and standard deviation σ = 30, what is her standardized score?
Draw by hand or in Excel fully labelled curves on a common scale to represent two sets of scores where: b. Mean = 50, Standard Deviation = 2, Mean = 50, Standard Deviation = 5. CUA
The table available below shows the costs per mile (in cents) for a sample of automobiles. At a = 0.01, can you conclude that at least one mean cost per mile is different from the others? Click on the icon to view the data table. Let Hss, µms, HLs, Hsuy and μMy represent the mean costs per mile for small sedans, medium sedans, large sedans, SUV 4WDs, and minivans respectively. What are the hypotheses for this test? A. Ho: Hss HMS HLS="SUV HMV H₂: Not all the means are equal. = B. Ho: Hss HMS = μLS="SUV = HMV Ha: Hss #HMS # μLS *μSUV HMV OC. Ho: Not all the means are equal. Ha: Hss HMS HLS HSUV HMV Ho: Hss #HMS HLS ‡μSUV * µMV Ha: Hss HMS = μLS="SUV=MV What is the test statistic? FSTAT (Round to two decimal places as needed.) =
The full question didn't fit in one part so I attached 2 photos.
The table available below shows the weights (in pounds) for a sample of vacuum cleaners. The weights are classified according to vacuum cleaner type. At a = 0.10, can you conclude that at least one mean vacuum cleaner weight is different from the others? Click the icon to view the vacuum cleaner weight data. Let μBU, BLU, and μTC represent the mean weights for bagged upright, bagless upright, and top canister vacuums respectively. What are the hypotheses for this test? A. Ho: At least one of the means is different. Ha: MBUHBLUPTC B. Ho: "BU HBLU HTC # Ha: MBUHBLUPTC C. Ho: MBUHBLU = HTC Ha: At least one of the means is different. D. Ho: MBU - HBLU = μTC Ha: HBU #BLU HTC What is the test statistic? F = 12.56 (Round to two decimal places as needed.) What is the P-value? P-value = 0.000624 (Round to three decimal places as needed.)
The quantitative subtest of the Graduate Record Exam (GRE) has a mean of 500 and a standard deviation of 100. What GRE score would correspond to a z score of 1.50? a. 600 b. 500 c. 340 d. 650
A successful basketball player has a height of 6 feet 11 inches, or 211 cm. Based on statistics from a data set, his height converts to the z score of 5.17. How many standard deviations is his height above the mean?
A normally distributed data set has a mean of O and a standard deviation of 2. What is the percent of values between -6.0 and 6.0? (make sure to include % sign in answer.)