The frame has an original loading system of four applied forces and one applied couple moment. Replace this loading system by an equivalent resultant force and couple moment acting at point B. (FR), (M2)», F3 B A (FR), dz ¥F4 Original System Equivalent System Assume the following values: d1 = 0.990 m , d2 = 1.14 m , d3 = 0.540 m , d4 = 2.08 m , F1 = 502 N , F2 = 300 N , F3 = 508 N , F4 = 402 N , and MA = 1507 N · m . Express the Cartesian components of the resultant force and the couple moment in newtons and newton-meters to three significant figures separated by commas.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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**Replacement of Original Loading System with Equivalent System**

**Description of the Problem:**
The frame depicted has an original loading system consisting of four applied forces and one couple moment. Your task is to replace this loading system with an equivalent resultant force and couple moment, both acting at point B.

**Diagrams:**

1. **Original System:**
   - The force \( F_1 \) acts at the left end of the horizontal member at point \( A \), with a distance \( d_1 \) to point \( B \).
   - The force \( F_2 \) acts to the right of \( F_1 \), with a distance \( d_2 \) to point \( B \).
   - The force \( F_3 \) acts downward at \( B \).
   - The force \( F_4 \) acts downward on the vertical member at a distance \( d_3 \) below point \( B \).
   - The couple moment \( M_A \) acts at point \( A \).

2. **Equivalent System:**
   - A resultant force \( (F_R) \) acts at point \( B \).
   - A resultant couple moment \( (M_R) \) acts at point \( B \).

**Given Data:**
- Distance Values: 
  - \( d_1 = 0.990 \, \text{m} \)
  - \( d_2 = 1.14 \, \text{m} \)
  - \( d_3 = 0.540 \, \text{m} \)
  - \( d_4 = 2.08 \, \text{m} \)
- Force Values:
  - \( F_1 = 502 \, \text{N} \)
  - \( F_2 = 300 \, \text{N} \)
  - \( F_3 = 508 \, \text{N} \)
  - \( F_4 = 402 \, \text{N} \)
- Moment Value:
  - \( M_A = 1507 \, \text{N} \cdot \text{m} \)

**Objective:**
Express the Cartesian components of the resultant force and the couple moment at point \( B \) in newtons and newton-meters to three significant figures.

**Solution Format:**
\[
(F_R)_x,
Transcribed Image Text:**Replacement of Original Loading System with Equivalent System** **Description of the Problem:** The frame depicted has an original loading system consisting of four applied forces and one couple moment. Your task is to replace this loading system with an equivalent resultant force and couple moment, both acting at point B. **Diagrams:** 1. **Original System:** - The force \( F_1 \) acts at the left end of the horizontal member at point \( A \), with a distance \( d_1 \) to point \( B \). - The force \( F_2 \) acts to the right of \( F_1 \), with a distance \( d_2 \) to point \( B \). - The force \( F_3 \) acts downward at \( B \). - The force \( F_4 \) acts downward on the vertical member at a distance \( d_3 \) below point \( B \). - The couple moment \( M_A \) acts at point \( A \). 2. **Equivalent System:** - A resultant force \( (F_R) \) acts at point \( B \). - A resultant couple moment \( (M_R) \) acts at point \( B \). **Given Data:** - Distance Values: - \( d_1 = 0.990 \, \text{m} \) - \( d_2 = 1.14 \, \text{m} \) - \( d_3 = 0.540 \, \text{m} \) - \( d_4 = 2.08 \, \text{m} \) - Force Values: - \( F_1 = 502 \, \text{N} \) - \( F_2 = 300 \, \text{N} \) - \( F_3 = 508 \, \text{N} \) - \( F_4 = 402 \, \text{N} \) - Moment Value: - \( M_A = 1507 \, \text{N} \cdot \text{m} \) **Objective:** Express the Cartesian components of the resultant force and the couple moment at point \( B \) in newtons and newton-meters to three significant figures. **Solution Format:** \[ (F_R)_x,
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