The fox population in a certain region has an annual growth rate of 7 percent per year. It is estimated that the population in the year 2000 was 24200. (a) Find a function that models the population t years after 2000 (t = 0 for 2000). %3D Your answer is P(t) (b) Use the function from part (a) to estimate the fox population in the year 2008. Your answer is (the answer should be an integer)

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### Population Growth Problem Set

#### Problem Statement:
The fox population in a certain region has an annual growth rate of 7 percent per year. It is estimated that the population in the year 2000 was 24,200.

#### Tasks:

1. **Find a Function That Models the Population**
   - Goal: Develop a mathematical function that represents the fox population \( t \) years after the year 2000 (\( t = 0 \) for the year 2000).
   - Answer format: \( P(t) = \) __________

2. **Estimate the Fox Population in 2008 Using the Function from Part (a)**
   - Goal: Use the developed function to estimate the fox population in the year 2008.
   - Answer format: The population estimate should be an integer.
   - Answer format: The answer is (the answer should be an integer) __________

#### Solution:

(a) **Find a Function that Models the Population**

To model the fox population, we use the formula for exponential growth:

\[ 
P(t) = P_0 (1 + r)^t 
\]

Where:
- \( P(t) \) is the population at time \( t \),
- \( P_0 \) is the initial population (24,200 in the year 2000),
- \( r \) is the annual growth rate (7% or 0.07),
- \( t \) is the number of years after 2000.

So the function that models the population \( t \) years after 2000 is:

\[ 
P(t) = 24200 \times (1 + 0.07)^t 
\]

(b) **Estimate the Fox Population in the Year 2008**

For the year 2008, \( t = 2008 - 2000 = 8 \).

Using the function from part (a):

\[ 
P(8) = 24200 \times (1.07)^8 
\]

Calculate \( (1.07)^8 \):

\[
(1.07)^8 \approx 1.718186
\]

Now multiply by the initial population:

\[ 
P(8) \approx 24200 \times 1.718186 \approx 41580 
\]

So, the estimated fox population in the year 2008 is approximately 41,580. 

**Your answer is:**

\[
Transcribed Image Text:### Population Growth Problem Set #### Problem Statement: The fox population in a certain region has an annual growth rate of 7 percent per year. It is estimated that the population in the year 2000 was 24,200. #### Tasks: 1. **Find a Function That Models the Population** - Goal: Develop a mathematical function that represents the fox population \( t \) years after the year 2000 (\( t = 0 \) for the year 2000). - Answer format: \( P(t) = \) __________ 2. **Estimate the Fox Population in 2008 Using the Function from Part (a)** - Goal: Use the developed function to estimate the fox population in the year 2008. - Answer format: The population estimate should be an integer. - Answer format: The answer is (the answer should be an integer) __________ #### Solution: (a) **Find a Function that Models the Population** To model the fox population, we use the formula for exponential growth: \[ P(t) = P_0 (1 + r)^t \] Where: - \( P(t) \) is the population at time \( t \), - \( P_0 \) is the initial population (24,200 in the year 2000), - \( r \) is the annual growth rate (7% or 0.07), - \( t \) is the number of years after 2000. So the function that models the population \( t \) years after 2000 is: \[ P(t) = 24200 \times (1 + 0.07)^t \] (b) **Estimate the Fox Population in the Year 2008** For the year 2008, \( t = 2008 - 2000 = 8 \). Using the function from part (a): \[ P(8) = 24200 \times (1.07)^8 \] Calculate \( (1.07)^8 \): \[ (1.07)^8 \approx 1.718186 \] Now multiply by the initial population: \[ P(8) \approx 24200 \times 1.718186 \approx 41580 \] So, the estimated fox population in the year 2008 is approximately 41,580. **Your answer is:** \[
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