The formula for the cross-product of a three-dimensional vector in terms of its components is a little more complicated than its two-dimensional counterpart. Let u = (a₁, a2, a3) and v = (b1,b2, b3). The matrix formula is as follows. i j k u x V = a1 a2 a3 b1 b₂ b3 Substitute the components into the formula and then expand along the first row. i 0 2 UX V = j -4 2 k 2 -2(2)) - i(0(C ] − 4 )i + (0 + [ - 2(2)) + k(0(2) - 2([
The formula for the cross-product of a three-dimensional vector in terms of its components is a little more complicated than its two-dimensional counterpart. Let u = (a₁, a2, a3) and v = (b1,b2, b3). The matrix formula is as follows. i j k u x V = a1 a2 a3 b1 b₂ b3 Substitute the components into the formula and then expand along the first row. i 0 2 UX V = j -4 2 k 2 -2(2)) - i(0(C ] − 4 )i + (0 + [ - 2(2)) + k(0(2) - 2([
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![The formula for the cross-product of a three-dimensional vector in terms of its components is a little more complicated than its two-dimensional counterpart. Let u =
(2₁, 22, 23) and
V = (b1,b2, b3). The matrix formula is as follows.
i j k
u x V = a1 a2 a3
b1 b2 b3
Substitute the components into the formula and then expand along the first row.
12₂2
u x V =
=
=
=
ij
0 -4
2
i(-4(C
k
2
]) — 2(2²)) - i(0([
4)i - ( [
]]) − 2(2)) + k(0(2) − 2([
)k
- 4)i + (0 +](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8d272df0-6234-4a67-bf97-6ce5f2f74b53%2F04d22839-cff8-4dea-9a11-329df9cb96a1%2Fmsirhaa_processed.png&w=3840&q=75)
Transcribed Image Text:The formula for the cross-product of a three-dimensional vector in terms of its components is a little more complicated than its two-dimensional counterpart. Let u =
(2₁, 22, 23) and
V = (b1,b2, b3). The matrix formula is as follows.
i j k
u x V = a1 a2 a3
b1 b2 b3
Substitute the components into the formula and then expand along the first row.
12₂2
u x V =
=
=
=
ij
0 -4
2
i(-4(C
k
2
]) — 2(2²)) - i(0([
4)i - ( [
]]) − 2(2)) + k(0(2) − 2([
)k
- 4)i + (0 +
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
