Can you please help me with this C++ program? I am using Atom as my program. The text provides sample output for a program that calculates combinations of objects in groups. Here's a transcribed version suitable for an educational context:---**Sample Output**1. The number of combinations of 1 object in groups of 1 is 1.2. The number of combinations of 2 objects in groups of 1 is 2.3. The number of combinations of 2 objects in groups of 2 is 2.4. The number of combinations of 3 objects in groups of 1 is 3.5. The number of combinations of 3 objects in groups of 2 is 3.6. The number of combinations of 3 objects in groups of 3 is 6.7. The number of combinations of 4 objects in groups of 1 is 4.8. The number of combinations of 4 objects in groups of 2 is 6.9. The number of combinations of 4 objects in groups of 3 is 4.10. The number of combinations of 4 objects in groups of 4 is 1.11. The number of combinations of 5 objects in groups of 1 is 5.12. The number of combinations of 5 objects in groups of 2 is 10.13. The number of combinations of 5 objects in groups of 3 is 10.14. The number of combinations of 5 objects in groups of 4 is 5.15. The number of combinations of 5 objects in groups of 5 is 1.16. The number of combinations of 6 objects in groups of 1 is 6.17. The number of combinations of 6 objects in groups of 2 is 15.18. The number of combinations of 6 objects in groups of 3 is 20.19. The number of combinations of 6 objects in groups of 4 is 15.20. The number of combinations of 6 objects in groups of 5 is 6.21. The number of combinations of 6 objects in groups of 6 is 1.---**Note:** The understanding of combinations here assumes the general formula for combinations, defined as \( C(n, r) = \frac{n!}{r!(n-r)!} \), where \( n \) is the total number of objects, \( r \) is the number of objects to choose, and \( ! \) denotes The formula for a combination of \( n \) objects in groups of \( r \) is \( n!/(n-r)! \).- A use for this formula would be to calculate how many ways five people can win a race where there is a 1st, 2nd, and 3rd place.- This is the same as saying how many ways can you order five objects in only three positions.- Using the above formula, we would set \( n=5 \) and \( r=3 \) and calculate \( 5!/(5-3)! \), which simplifies to \( 5*4*3 \) or 60 possible ways.Write a function `factorial()` which accepts an integer as input and returns the factorial of the input.Write a function `combinations()` which accepts 2 integer parameters and calls the `factorial()` function to calculate the number of combinations.Write a program which uses the above functions in a nested loop and calculates all combinations for 1 to 6 objects.**Sample output**The number of combinations of 1 objects in groups of 1 is 1The number of combinations of 2 objects in groups of 1 is 2 The number of combinations of 2 objects in groups of 2 is 2The number of combinations of 3 objects in groups of 1 is 3 The number of combinations of 3 objects in groups of 2 is 6 The number of combinations of 3 objects in groups of 3 is 6The number of combinations of 4 objects in groups of 1 is 4 The number of combinations of 4 objects in groups of 2 is 12 The number of combinations of 4 objects in groups of 3 is 24 The number of combinations of 4 objects in groups of 4 is 24The number of combinations of 5 objects in groups of 1 is 5 The number of combinations of 5 objects in groups of 2 is 20 The number of combinations of 5 objects in groups of 3 is 60 The number of combinations of 5 objects in groups of 4 is 120 The number of combinations of 5 objects in groups of 5 is 120The number of combinations of 6 objects in groups of 1 is 6 The number of combinations of 6 objects in groups of 2

Name: Can you please help me with this C++ program? I am using Atom as my pr
Uploaded: 2024-03-20T06:51:23.000Z
Channel: Bartleby
Description: Can you please help me with this C++ program? I am using Atom as my program. The text provides sample output for a program that calculates combinations of objects in groups. Here's a transcribed version suitable for an educational context:---**Sample