The form of the partial fraction decomposition of a rational function is given below. A = B = C = 4x²-3x + 27 (x+3)(x² +9) = A x + 3 + Bx + C x² +9

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The form of the partial fraction decomposition of a rational function is given below.
A = B=0C =
Now evaluate the indefinite integral.
4x²-3x + 27
(x+3)(x² +9)
dx
4x²-3x+27
(x+3)(x² +9)
A
x +3
Bx + C
x² +9
Transcribed Image Text:The form of the partial fraction decomposition of a rational function is given below. A = B=0C = Now evaluate the indefinite integral. 4x²-3x + 27 (x+3)(x² +9) dx 4x²-3x+27 (x+3)(x² +9) A x +3 Bx + C x² +9
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