The force exerted by an electric charge at the origin on a charged particle at the point (x, y, z) with position KT vector 7=(x, y, z) is where K is constant. = > 171³ Assume K = 30. Find the work done as the particle moves along a straight line from (3,0,0) to (3,4,2).
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- A 9.00-kg particle moves from the origin to position ©, having coordinates x = 4.50 m and y = 4.50 m as shown in the figure. One force on the particle is the gravitational force acting in the negative y direction. Using the equation (W = FAr cos e = F . Ař), calculate the work done by the gravitational force in going from O to © along the following paths. у (m) C) (x, y) х (m) (a) the purple path (o0© (b) the red path (OB© (c) the blue path (O© (d) Your results should all be identical. Why?A particle moves in the xy plane (see the figure below) from the origin to a point having coordinates x = 7.00 m and y = 4.00 m under the influence of a force given by 7 = -2y²1 - 3x1. y (m) 2 (7.00, 4.00) x (m) (a) What is the work done on the particle by the force F if it moves along path 1 (shown in red)? -84 (b) What is the work done on the particle by the force F if it moves along path 2 (shown in blue)? -224 (c) What is the work done on the particle by the force F if it moves along path 3 (shown in green)? -32.7 X Your response differs from the correct answer by more than 10%. Double check your calculations. J (d) Is the force conservative or nonconservative? conservative nonconservativeA particle moves along a curved path y(x) = (10 m){1+cos[(0.1 m−1)x]} , from x = 0 to x = 10π m, subject to a tangential force of variable magnitude F(x) = (10 N)sin[(0.1 m−1)x]. How much work does the force do? (Hint: Consult a table of integrals or use a numerical integration program.)
- A can of sardines is made to move along an x axis from x = 0.44 m to x = 1.49 m by a force with a magnitude given by F = e-6x, with x in meters and F in Newtons. How much work is done on the %3D can by the force?Please circle answerA 7.00-kg particle moves from the origin to position ©, having coordinates x = 6.50 m and y = 6.50 m as shown in the figure. One force on the particle is the gravitational force acting in the negative y direction. Using the equation (W = FAr cos 0 = F · Ař), calculate the work done by the gravitational force in going from O to © along the following paths. у (m) B (х, у) x (m) (a) the purple path (o0©) (b) the red path (O®© (c) the blue path (O© (d) Your results should all be identical. Why? This answer has not been graded yet.
- The force on a particle is described by 2x^3−6 at a point x along the x-axis. Find the work done in moving the particle from the origin to x=7.The force exerted by an electric charge at the origin on a charged particle at the point (æ, y, z) is F(7) KT where K is constant. (x, y, z) with position vector Assume K = 30. Find the work done as the particle moves along a straight line from (3,0,0) to (3,4,5)Problem Thirteen. A potential energy function is given by U(r)=U2 where o = 2.00 m r r and U, = 1.00 J. Find the magnitude of the force at r= 1.00 m. Give an answer in kN. 25.) (A) 280 (В) 106 (С) 420 (D) 470 (E) 530
- Given: A shopper pushes a grocery cart for a distance 21 m at constant speed on level ground, against a 37.5 N frictional force. He pushes in a direction 22.5° below the horizontal. What is the work done on the cart by friction, in joules? What is the work done on the cart by the gravitational force, in joules? What is the work done on the cart by the shopper, in joules? Find the magnitude of the force, in newtons, that the shopper exerts on the cart. What is the total work done on the cart, in joules?The force F = (6.82 N)i + (4.75 N)j acts on a particle as it moves along a straight line from Cartesian coordinate (0.77 m, 1.58 m) to (7.38 m, 8.37 m). What is the work done, in joules, by the force?If the potential energy of a particle is given by U (r, y, 2) = –kry?2³, find the force associated with this potential energy where k is a positive constant. k(2x²yz³i+y²z³j + xy²2²k) kry²2*(i + ĵ + k) k(y²2³i + 2xyz³j + 3xy²2²k) -kry 2*(i +j+ k) 33 3 k(y²2*i+ xyz°j +xy²2² k)