The force-couple system shown can be replaced by a single equivalent couple CR. Determine CR. Can be done in two ways: using the fact that the 80 N can be split into 50+30, we have a 50 N-forces couple and a 30 N-forces couple and the 15 Nm couple.Then add the moments. OR simply compute moments about any point, let us use B. 720 mm 80 N M80 0.48k × (–80i) -38.4j 480 mm M30 15000 N mm M50 -0.72j × 50i = 36k 50 N MGiven -15j 30 N CR -53.4j + 36k Nm

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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I dont anderstand why M30 is = to 0

Can be done in two ways: using the fact that the 80 N can be
split into 50+30, we have a 50 N-forces couple and a 30 N-forces
couple and the 15 Nm couple.Then add the moments. OR simply
compute moments about any point, let us use B.
The force-couple system shown can be replaced by a single equivalent couple CR. Determine CR.
720 mm
80 N
M80
0.48k × (-80i) = –38.4j
480 mm
M30
M50
-0.72j x 50i = 36k
15000 N mm
50 N
MGiven
-15j
B.
CR
-53.4j + 36k Nm
10N
Transcribed Image Text:Can be done in two ways: using the fact that the 80 N can be split into 50+30, we have a 50 N-forces couple and a 30 N-forces couple and the 15 Nm couple.Then add the moments. OR simply compute moments about any point, let us use B. The force-couple system shown can be replaced by a single equivalent couple CR. Determine CR. 720 mm 80 N M80 0.48k × (-80i) = –38.4j 480 mm M30 M50 -0.72j x 50i = 36k 15000 N mm 50 N MGiven -15j B. CR -53.4j + 36k Nm 10N
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