The force acting on a moving charged particle in a magnetic field B is F = q(v × B) where q is the electric charge of the particle, and v is its velocity. Suppose that a particle moves in the (x, y) plane with a uniform B in the z direction. Assuming Newton’s second law, m dv/dt = F, show that the force and velocity are perpendicular and that both have constant magnitude. Hint: Find (d/dt)(v · v).
The force acting on a moving charged particle in a magnetic field B is F = q(v × B) where q is the electric charge of the particle, and v is its velocity. Suppose that a particle moves in the (x, y) plane with a uniform B in the z direction. Assuming Newton’s second law, m dv/dt = F, show that the force and velocity are perpendicular and that both have constant magnitude. Hint: Find (d/dt)(v · v).
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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The force acting on a moving charged particle in a magnetic field B is F = q(v × B) where q is the electric charge of the particle, and v is its velocity. Suppose that a particle moves in the (x, y) plane with a uniform B in the z direction. Assuming Newton’s second law, m dv/dt = F, show that the force and velocity are perpendicular and that both have constant magnitude. Hint: Find (d/dt)(v · v).
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