The following three independent random samples are obtained from three normally distributed populationswith equal variances. The dependent variable is starting hourly wage, and the groups are the types ofposition (internship, co-op, work study). Round answers to 4 decimal places.InternshipCo-opWork Study13.513.514.2514.513.2514.514.2513.513.251312.513.7514.751314.512.512.7512.7513.2513.512.513.251413.513.7513.51413.25131413.2512.513.513.513.512.513.512.7514.51414.51414.514.514.2514.2513.7514.7512.7512.7513.25Use Excel to conduct a single-factor ANOVA to determine if the group means are equal using a = 0.01.Group means:Internship:Со-ор:Work Study:Fill in the summary table for the ANOVA test:dfMSBetweenWithinTotalFrom this table, obtain the necessary statistics for the ANOVA:ANOVA summary statistics:Test Statistic =P-value =Conclusion: Select an answer

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Description: The following three independent random samples are obtained from three normally distributed populationswith equal variances. The dependent variable is starting hourly wage, and the groups are the types ofposition (internship, co-op, work study). Rou

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The following three independent random samples are obtained from three normally distributed populations with equal variances. The dependent variable is starting hourly wage, and the groups are the types of position (internship, co-op, work study). Round answers to 4 decimal places. Internship Work Study Co-op 13.5 13.5 14.5 14.25 14.5 13.25 14.25 13.5 13.25 13 14.75 13.75 14.5 12.5 13 12.5 13.5 13.25 12.5 12.75 12.75 13.25 14 13.5 13.75 13.5 13 14 13.25 14 13.25 13.5 12.5 13.5 13.5 12.5 14.5 13.5 12.75 14 14.5 14 14.5 14.5 14.25 14.25 13.75 14.75 12.75 12.75 13.25 Use Excel to conduct a single-factor ANOVA to determine if the group means are equal using a = 0.01. Group means: Internship: Co-op: Work Study: Fill in the summary table for the ANOVA test: df MS Between Within Total From this table, obtain the necessary statistics for the ANOVA: ANOVA summary statistics: Test Statistic = p-value = Conclusion: Select an answer

The following three independent random samples are obtained from three normally distributed populations with equal variances. The dependent variable is starting hourly wage, and the groups are the types of position (internship, co-op, work study). Round answers to 4 decimal places. Internship Work Study Co-op 13.5 13.5 14.5 14.25 14.5 13.25 14.25 13.5 13.25 13 14.75 13.75 14.5 12.5 13 12.5 13.5 13.25 12.5 12.75 12.75 13.25 14 13.5 13.75 13.5 13 14 13.25 14 13.25 13.5 12.5 13.5 13.5 12.5 14.5 13.5 12.75 14 14.5 14 14.5 14.5 14.25 14.25 13.75 14.75 12.75 12.75 13.25 Use Excel to conduct a single-factor ANOVA to determine if the group means are equal using a = 0.01. Group means: Internship: Co-op: Work Study: Fill in the summary table for the ANOVA test: df MS Between Within Total From this table, obtain the necessary statistics for the ANOVA: ANOVA summary statistics: Test Statistic = p-value = Conclusion: Select an answer

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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In this exercise involving paired differences, consider that it is reasonable to assume the populations being compared have approximately the same shape and that the distribution of paired differences is approximately symmetric. A sample of 10 men was used in a study to test the effects of a relaxant on the time required to fall asleep. Suppose data for 10 subjects showing the number of minutes required to fall asleep with and without the relaxant follow. Relaxant Subject No Yes 1 14 14 9 2 13 10 3 23 12 4. 6 10 5 9 8 16 8 5 7 00 8 10 8 11 7 9 13 11 10 8 6 Use a 0.05 level of significance to determine whether the relaxant reduces the median time required to fall asleep. State the null and alternative hypotheses. Ho: Median time without relaxant - Median time with relaxant ≤ 0 Ha : Median time without relaxant - Median time with relaxant > 0 O Ho: Median time without relaxant - Median time with relaxant H : Median time without relaxant O Ho: Median time without relaxant - = 0 Median…
Consider the following data: Step 1 of 3: Calculate the value of the sample variance. Round your answer to one decimal place. Answer How to enter your answer (opens in new window) stical Tables nomial Probabilities nomial Cumulative Poisson Probabilities Poisson Cumulative andard Normal Table t Table - Chi Square F Table - Pearson Correlation Coefficient Nonparametrics - Misc. q Table -2, -2, -8,-8, -2, -8, 12 N ww 3.1 3.0 2.9 2.8 2.7 2.6 2.5 Copy Data Tables Keypad Keyboard Shortcuts 0.07 0.08 0.09 3.3 3.2 Standard Normal Probabilities (z to ∞) 0.00 0.01 0.02 0.03 0.04 0.05 0.06 3.4 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.000 0.0005 0.0005 0.0005 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.000 0.0007 0.0007 0.0006 0.0006 0.0006 0.0006 0.0006 0.0005 0.0005 0.000 0.0010 0.0009 0.0009 0.0009 0.0008 0.0008 0.0008 0.0008 0.0007 0.000 0.0013 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011 0.0011 0.0010 0.001 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 0.0015 0.0014…
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Do rats take the same amount of time on average than hamsters to travel through a maze? The table below shows the times in seconds that the rats and hamsters took. Rats: 31, 26, 35, 34, 31, 39, 39, 6 Hamsters: 36, 35, 16, 29, 20, 25, 28, 37 Assume that both populations follow a normal distribution. What can be concluded at the a = 0.05 level of significance level of significance? For this studv, we should use Select an answer a. The null and alternative hypotheses would be: Ho: Select an answer v Select an answer v Select an answer V (please enter a decimal) H1: Select an answer v Select an answer v v (Please enter a decimal) Select an answer b. The test statistic ?v= (please show your answer to 3 decimal places.) c. The p-value = (Please show your answer to 4 decimal places.) d. The p-value is ? va e. Based on this, we should Select an answer v the null hypothesis. f. Thus, the final conclusion is that ... O The results are statistically insignificant at a = 0.05, so there is…
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A hospital wants to determine if the type of treatment for pneumonia is a factor in recovery time? The table below shows the number of days to recovery for several randomly selected pneumonia patients that had various types of treatment. Sent Home With Medicine A Few Hours in the Hospital Overnight Hospital Stay 25 16 8 15 8 16 15 24 10 17 20 6 17 16 10 28 20 17 12 17 13 26 23 Assume that all distributions are normal, the three population standard deviations are all the same, and the data was collected independently and randomly. Use a level of significance of α=0.01α=0.01.H0: μ1=μ2=μ3H0: μ1=μ2=μ3H1:H1: At least two of the means differ from each other. For this study, we should use Incorrect The test-statistic for this data = (Please show your answer to 3 decimal places.) The p-value for this sample = (Please show your answer to 4 decimal places.) The p-value is Incorrect αα Base on this, we should Incorrect hypothesis As such, the final…
A hospital wants to determine if the type of treatment for pneumonia is a factor in recovery time? The table below shows the number of days to recovery for several randomly selected pneumonia patients that had various types of treatment. Sent Home With Medicine A Few Hours in the Hospital Overnight Hospital Stay 14 21 17 12 22 7 16 11 13 27 10 19 15 8. 10 19 16 4 23 24 19 16 8 18 12 Assume that all distributions are normal, the three population standard deviations are all the same, and the data was collected independently and randomly. Use a level of significance of a = 0.05. Ho: µ1 = µ2 = 43 H1: At least two of the means differ from each other. 1. For this study, we should use Select an answer O 2. The test-statistic for this data = (Please show your answer to 3 decimal places.) 3. The p-value for this sample = (Please show your answer to 4 decimal places.) 4. The p-value is Select an answer 5. Base on this, we should Select an answer O hypothesis 6. As such, the final conclusion is…