The following thermochemical equation is for the reaction of water(1) to form hydrogen(g) and oxy 2H,O(1)- →2H2(g) + O2(g) ΔΗ-572 kJ

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The following thermochemical equation is for the reaction of water (l) to form hydrogen (g) and oxygen (g).

\[ \text{2H}_2\text{O(l)} \rightarrow \text{2H}_2\text{(g)} + \text{O}_2\text{(g)} \quad \Delta H = 572 \, \text{kJ} \]

How many grams of H\(_2\)O(l) would be made to react if 108 kJ of energy were provided?

\[ \_\_\_\_\_ \, \text{grams} \]
Transcribed Image Text:The following thermochemical equation is for the reaction of water (l) to form hydrogen (g) and oxygen (g). \[ \text{2H}_2\text{O(l)} \rightarrow \text{2H}_2\text{(g)} + \text{O}_2\text{(g)} \quad \Delta H = 572 \, \text{kJ} \] How many grams of H\(_2\)O(l) would be made to react if 108 kJ of energy were provided? \[ \_\_\_\_\_ \, \text{grams} \]
**Thermochemical Reaction of Hydrogen Sulfide with Water**

The following thermochemical equation represents the reaction of hydrogen sulfide (H₂S) in the gaseous state with liquid water (H₂O) to form hydrogen gas (H₂) and sulfur dioxide gas (SO₂).

**Reaction:**

\[ \textbf{H}_2\textbf{S(g)} + 2 \textbf{H}_2\textbf{O(g)} \rightarrow 3 \textbf{H}_2\textbf{(g)} + \textbf{SO}_2\textbf{(g)} \hspace{10px} \Delta H = 207 \, \text{kJ} \]

**Details:**

- **ΔH (Enthalpy Change):** The enthalpy change for this reaction is 207 kJ. This value indicates the amount of energy absorbed during the reaction process.

**Problem Statement:**

Determine the amount of energy (in kJ) released or absorbed when 11.6 grams of hydrogen sulfide react with excess water. 

**Hint:**

An amount of energy is expressed as a positive number. The sign of ΔH in the thermochemical equation indicates whether energy is absorbed or evolved. In this context, a positive ΔH suggests that energy is absorbed during the reaction.

Fill in the blank: When 11.6 grams of hydrogen sulfide react with excess water, [ ] kJ of energy are [absorbed/evolved].
Transcribed Image Text:**Thermochemical Reaction of Hydrogen Sulfide with Water** The following thermochemical equation represents the reaction of hydrogen sulfide (H₂S) in the gaseous state with liquid water (H₂O) to form hydrogen gas (H₂) and sulfur dioxide gas (SO₂). **Reaction:** \[ \textbf{H}_2\textbf{S(g)} + 2 \textbf{H}_2\textbf{O(g)} \rightarrow 3 \textbf{H}_2\textbf{(g)} + \textbf{SO}_2\textbf{(g)} \hspace{10px} \Delta H = 207 \, \text{kJ} \] **Details:** - **ΔH (Enthalpy Change):** The enthalpy change for this reaction is 207 kJ. This value indicates the amount of energy absorbed during the reaction process. **Problem Statement:** Determine the amount of energy (in kJ) released or absorbed when 11.6 grams of hydrogen sulfide react with excess water. **Hint:** An amount of energy is expressed as a positive number. The sign of ΔH in the thermochemical equation indicates whether energy is absorbed or evolved. In this context, a positive ΔH suggests that energy is absorbed during the reaction. Fill in the blank: When 11.6 grams of hydrogen sulfide react with excess water, [ ] kJ of energy are [absorbed/evolved].
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