The following table shows the heart rate of students in a conditioning class after 1 minute of doing jumping jacks (beats per minute). 90 90 95 95 95 96 96 97 98 98 99 100 102 104 104 105 105 107 108 112 (a) Compute the five-number summary. Min = 90 Q1 = 95.2 Median = 98.5 Q3 = 104.75 Max = 112 (b) The overall shape of the distribution is right skewed than the median. (c) For these data, the mean will be greater (d) Do any of the heart rates appear to be an outlier? Explain.
The following table shows the heart rate of students in a conditioning class after 1 minute of doing jumping jacks (beats per minute). 90 90 95 95 95 96 96 97 98 98 99 100 102 104 104 105 105 107 108 112 (a) Compute the five-number summary. Min = 90 Q1 = 95.2 Median = 98.5 Q3 = 104.75 Max = 112 (b) The overall shape of the distribution is right skewed than the median. (c) For these data, the mean will be greater (d) Do any of the heart rates appear to be an outlier? Explain.
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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Do any of the heart rates appear to be an outlier? Explain

Transcribed Image Text:The following table shows the heart rate of students in a conditioning class after 1 minute of doing jumping jacks (beats per minute).
90 90 ||95 95 95 |96 96 97 |98 98
99 100 102104| 104 105|105 107 108 112
(a) Compute the five-number summary.
Min = 90
06%3D
Q1 = 95.2
%3D
Median
98.5
%3D
Q3 = 104.75
%3D
Max = 112
%3D
(b) The overall shape of the distribution is right skewed
(c) For these data, the mean will be greater
than the median.
(d) Do any of the heart rates appear to be an outller? Explain.
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