The following table represents the prices of copper futures (in USD) from theperiod of time from 14.06.2020 to 06.06.2021, where t is time since 14.06.2020 (measured in weeks) and f(t) is the corresponding price: t f(t) 0 2.6655 1 2.7120 2 2.7800 3 2.9255 4 2.9355 5 2.9220 6 2.9110 7 2.8445 8 2.9070 t f(t) 9 2.9570 10 3.0365 11 3.0810 12 3.0590 13 3.1215 14 2.9785 15 2.9900 16 3.0800 17 3.0720 t f(t) 18 3.1305 19 3.0565 20 3.1635 21 3.1890 22 3.3125 23 3.4210 24 3.5285 25 3.5340 26 3.6370 t f(t) 27 3.5675 28 3.5240 29 3.6800 30 3.6070 31 3.6315 32 3.5565 33 3.6265 34 3.7885 35 4.0775 t f(t) 36 4.0925 37 4.0755 38 4.1400 39 4.1130 40 4.0680 41 3.9905 42 4.0400 43 4.1680 44 4.3360 t f(t) 45 4.4680 46 4.7485 47 4.6545 48 4.4810 49 4.6775 50 4.5290 51 4.5375     Let L(x) be the third Lagrange polynomial for the function f(x) with the nodes X0 = 0,   x1 = 12, x2 = 42,  x3 = 50. (i) Find the value L(22) of the Lagrange polynomial at x = 22 and the relative error in the approximation f(22) ≈ L(22): (ii) Find the value L(51) of the Lagrange polynomial at x = 51 and the relative error in the approximation f(51) ≈ L(51): All calculations are to be carried out in the FPA5, and the computational results are to be presented in two standard output tables for themethod of the form xk x0 x1 … xn   yk= f(xk) y0 y1 … yn   Lk(x) L0(x) L1(x) … Ln(x) Total, L(x) ykLk(x) y0L0(x) y1L1(x) … ynLn(x) ∑kykLk(x)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The following table represents the prices of copper futures (in USD) from theperiod of time from 14.06.2020 to 06.06.2021, where t is time since 14.06.2020 (measured in weeks) and f(t) is the corresponding price:

t

f(t)

0

2.6655

1

2.7120

2

2.7800

3

2.9255

4

2.9355

5

2.9220

6

2.9110

7

2.8445

8

2.9070

t

f(t)

9

2.9570

10

3.0365

11

3.0810

12

3.0590

13

3.1215

14

2.9785

15

2.9900

16

3.0800

17

3.0720

t

f(t)

18

3.1305

19

3.0565

20

3.1635

21

3.1890

22

3.3125

23

3.4210

24

3.5285

25

3.5340

26

3.6370

t

f(t)

27

3.5675

28

3.5240

29

3.6800

30

3.6070

31

3.6315

32

3.5565

33

3.6265

34

3.7885

35

4.0775

t

f(t)

36

4.0925

37

4.0755

38

4.1400

39

4.1130

40

4.0680

41

3.9905

42

4.0400

43

4.1680

44

4.3360

t

f(t)

45

4.4680

46

4.7485

47

4.6545

48

4.4810

49

4.6775

50

4.5290

51

4.5375

 

 

Let L(x) be the third Lagrange polynomial for the function f(x) with the nodes

X0 = 0,   x1 = 12, x2 = 42,  x3 = 50.

(i) Find the value L(22) of the Lagrange polynomial at x = 22 and the relative error in the approximation f(22) ≈ L(22):

(ii) Find the value L(51) of the Lagrange polynomial at x = 51 and the relative error in the approximation f(51) ≈ L(51):

All calculations are to be carried out in the FPA5, and the computational results are to be presented in two standard output tables for themethod of the form

xk

x0

x1

xn

 

yk= f(xk)

y0

y1

yn

 

Lk(x)

L0(x)

L1(x)

Ln(x)

Total, L(x)

ykLk(x)

y0L0(x)

y1L1(x)

ynLn(x)

kykLk(x)

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