The following table represents the joint probability distribution of the number of people waiting to cross intersection A and intersection B at any given time. B=0 B=1 B=2 B=3 PA (A= a) A = 0 0.062 0.12 0.04 0.13 A= 1 0.02 0.05 0.044 A= 2 0.07 0.06 0.11 0.01 A= 3 0.16 0.02 0.226 PB (B=b) 0.246 a. Determine the probability of three people waiting to cross intersection A and one person waiting to cross intersection B. Answer in fraction or in exact decimals b. What is the probability of a total of at most two people waiting to cross both intersections A and B? Answer in fraction or in exact decimals c. If there are at least two people waiting to cross intersection B, what is the probability of two people waiting to cross intersection A? Answer in exact fraction or rounded to at least 4 decimal places

The following table represents the joint probability distribution of the number of people waiting to cross intersection A and intersection B at any given time. B=0 B=1 B=2 B=3 PA (A= a) A = 0 0.062 0.12 0.04 0.13 A= 1 0.02 0.05 0.044 A= 2 0.07 0.06 0.11 0.01 A= 3 0.16 0.02 0.226 PB (B=b) 0.246 a. Determine the probability of three people waiting to cross intersection A and one person waiting to cross intersection B. Answer in fraction or in exact decimals b. What is the probability of a total of at most two people waiting to cross both intersections A and B? Answer in fraction or in exact decimals c. If there are at least two people waiting to cross intersection B, what is the probability of two people waiting to cross intersection A? Answer in exact fraction or rounded to at least 4 decimal places

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Suppose we are interested in the relationship between an individual's brown hair and skin color. Based on a random sample of LIU students, we have the following joint probability distribution given by: X-degree of brown hair color 2 3 4 0.12 0.01 0.05 0.07 0.07 0.12 0.09 0.16 Y- degree of skin color 2 0.12 3 0.16 | 0.03 The probability that an individual with degree of brown hair 2 has a degree of skin color 1 is: None of these 0.263 0.167 0.3
The following is the probability distribution for an athlete of winning medals. Medal (Event) Gold E1 Silver E2 Bronze E3 No medal E4 P(Ei) 0.10 0.15 0.20 0.55 Find the probability of earning a medal. Group of answer choices 0.45 0.9 0.15 0.75 0.25
Let X = {Email, In Person, Instant Message, Text Message}; P(Email) = 0.06 P(In Person) = 0.55 P(Instant Message) = 0.24 P(Text Message) = 0.15 Is this model a probability distribution? A. Yes. B. No. C. Maybe.
The joint probability distribution of the number X of cars and the number Y of buses per signal cycle at a proposed left-turn lane is displayed in the accompanying joint probability table below. y P(xy) 1 2. 0. .025 .015 .010 .050 .030 020 2. .125 .075 050 3. 150 090 060 4. 100 .060 040 050 .030 .020 Suppose the left-turn lane is to have a capacity of six cars, and that one bus is equivalent to three cars. What is the probability of an overflow duringa cycle? Select one: O 48 O 28 O38 0.18
The table below shows the probability distribution for forest fires each year, measured in square kilometers Square Km of Probability Forest Fires 200 0.03 400 0.19 600 0.36 800 0.27 1000 0.11 1200 0.04 Each square km of forest fire will cost the govemment $1440 to extinguish Calculate the expected cost per year to fight forest fires. Answer
Suppose the random variable Z follows a standard normal distribution. Then the probability is 0.20 that Z is less than the value O a. 0.84 O b. -0.84 O c. - 0.80 Od. 0.80
Refer to this figure to answer number 8- 10. The table below show the probability distribution of number of face mask sold per day. 1 2 3 5 6. 7 8. 10 0.07 P(x) P/x) 0.16 0.07 0.1 0.09 0.1 0.07 0.08 0.1 0.17 0.56 1.4 1.96 5.76 11.56 0.16 0.40 0.16 0.14 0.3 0.36 0.5 0.42 0.56 0.9 1.7 X-U -4.6 -3.6 -2.6 -1.6 -0.6 0.4 2.4 3.4 4.4 (x-)A2 (x-u)A2 *P(x) 21.16 12.96 6.76 2.56 0.36 0.16 19.36 3.39 0.91 0.68 0.23 0.04 0.01 1.16 3.29 8. What is ExP(x) =? A. 5.6 B. 6.5 C.7 D. 8 9. What is a? = E[(x - 4) P(x)] A. 5.9 %3D В. 8.6 С. 10.25 D. 11.35 10. If the standard deviation of the variance of problem number 9 is 3.20156, then how do we get the value of standard deviation given the value of variance? A. Vo? B. Va C. uP(x) D. o ololo-
Rem. A concerned parents group determined the number of commercials shown in each of the five children's programs over a period of time. Num of Commercials P(X = x 1.824 0.078 2.081 0.05 2.338 0.101 2.595 0.134 2.852 0.07 3.109 0.567 Consider the probability distribution table above. Determine the following: (a) Determine the mean = (b) Determine the Standard Deviation
Suppose you were given this Joint Probability Distribution: x=number of bars of signal strength x=number of bars of signal strength x=number of bars of signal strength x=number of bars of signal strength y=number of times city name is stated 1 2 3 Marginal probability distribution of y 4 0.15 0.1 0.05 0.3 3 0.02 0.1 0.05 0.17 2 0.02 0.03 0.2 0.25 1 0.01 0.02 0.25 0.28 0.2 0.25 0.55 Marginal probability distribution of x Marginal probability distribution of x Marginal probability distribution of x Marginal probability distribution of x Find the conditional mean and variance of Y|3 Mean = Variance =
A survey of almost 44,000 two-child families yielded the accompanying table. The probability distribution of x, the number of boys in a two-child family is given below. Find E(x) and give a practical interpretation of its value. Gender Configuration Proportion D Girl-girl (GG) Boy-girl (BG) Girl-Boy (GB) 0.215 0.267 0.256 P(x) 0.215 0.523 0.262 Boy-boy (BB) 0.262 Choose the correct answer below and fill in the answer box to complete your choice. (Round to three decimal places as needed.) O A. If a very large number of households were sampled, on average, there would be E(x) = boys. O B. If a very large number of two-child households were sampled, on average, there would be E(x) = boys. of getting a family with a boy. %3D O C. If a very large number of two-child households were sampled, there would be a probability of E(x) = O D. In the sample of 44,000 households, each household had E(x) = boys.