The following system of equations is to be solved using Newton-Raphson iteration: sinx-cosy-1=0 ex + xy² -4 = 0 If the values of x and y for the current iteration are x = 1.65 and y = 2.64, then element (2,2) of the Jacobian matrix evaluates as: (Enter your answer to four decimal places)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The following system of equations is to be solved using Newton-Raphson iteration:
sin x
cosy-1=0
ex + xy² -4 = 0
If the values of x and y for the current iteration are x = 1.65 and y = 2.64, then element (2,2) of the Jacobian matrix evaluates as: (Enter your
answer to four decimal places)
-
Transcribed Image Text:The following system of equations is to be solved using Newton-Raphson iteration: sin x cosy-1=0 ex + xy² -4 = 0 If the values of x and y for the current iteration are x = 1.65 and y = 2.64, then element (2,2) of the Jacobian matrix evaluates as: (Enter your answer to four decimal places) -
Expert Solution
Step 1

Given Data:

Let us consider the given system of equations is,

sinx -cosy-1=0ex+xy2-4=0

The values of current iteration is

x=1.65 y=2.64

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