The following signal was recorded using an accelerometer attached to the human body with a sampling rate of 100 Hz. We want to estimate the distance (in seconds) between the two smaller peaks of the signal (grey box). What is the minimum sampling rate that can be used to sample this signal, while still being able to separate the two smaller peaks? The text below should guide you through the question. Fill in the blanks for each step of the calculation. 150 100 50 -50 Дими 10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 Sample The distance between the two smaller peaks is 6 samples. This is equivalent to | 0.06 seconds. This translates to the frequency |17 Hz (please round to the nearest integer). This means the minimal sampling frequency to sample this signal is 34 Hz (please round to the nearest integer).
The following signal was recorded using an accelerometer attached to the human body with a sampling rate of 100 Hz. We want to estimate the distance (in seconds) between the two smaller peaks of the signal (grey box). What is the minimum sampling rate that can be used to sample this signal, while still being able to separate the two smaller peaks? The text below should guide you through the question. Fill in the blanks for each step of the calculation. 150 100 50 -50 Дими 10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 Sample The distance between the two smaller peaks is 6 samples. This is equivalent to | 0.06 seconds. This translates to the frequency |17 Hz (please round to the nearest integer). This means the minimal sampling frequency to sample this signal is 34 Hz (please round to the nearest integer).
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Transcribed Image Text:The following signal was recorded using an accelerometer attached to the human body with a sampling rate of 100 Hz.
We want to estimate the distance (in seconds) between the two smaller peaks of the signal (grey box). What is the minimum sampling rate that can be used to sample this signal,
while still being able to separate the two smaller peaks?
The text below should guide you through the question. Fill in the blanks for each step of the calculation.
150
100
50
-50
Дими
10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170
Sample
The distance between the two smaller peaks is 6 samples. This is equivalent to | 0.06
seconds. This translates to the frequency |17
Hz (please round to the
nearest integer). This means the minimal sampling frequency to sample this signal is 34
Hz (please round to the nearest integer).
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