The following results are for independent random samples takenfrom two populations. Suppose that we want to provide a 95%confidence interval for the difference between the two populationmeans.Sample 1Sample 2n1 = 20n2 = 30X1 = 22.5= 20.1S1 = 2.5S2 = 4.8(a) What is the point estimate of the difference between the twopopulation means?(b) What is the degrees of freedom for the t distribution?(c) At 95% confidence, what is the margin of error?

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Answered: The following results are for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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QUESTION 1 In a phone manufacturing company, the management would like to know the mean defective units per batch. Assume number of defective units follows the normal distribution, for a sample of 20 phones, the mean defective units was 52.38 phones with a standard deviation of 4. 34 Find only the Lower Limit of the confidence interval for the value of the population mean with 95% confidence interval. (Write your answer in 2 decimals places)
#21)
Your company sources motors from two suppliers: supplier A and supplier B. Your application requiresvery high maximum torque. You wish to know if there is a significant difference in maximum torque forthe motors from supplier A vs. supplier B. You sample 10 motors from each supplier and measure themaximum torque. The sample means and sample standard deviations are shown the following table. Is there evidence to conclude that one supplier is better than the other at a 95% confidence level?
An experiment is assessing the effect of exercise regimen on cholesterol level decrease. A random sample of 45 individuals is selected, and their cholesterol decrease after following the regimen is recorded. These decreases are assumed to be normally distributed with a known variance of 20. The sample mean decrease is found to be 30 units. Calculate the 99% confidence interval for the average cholesterol decrease of all individuals on this regimen.
Suppose that the height of Asian males aged 35-44 in the United States is normally distributed with a standard deviation of 3 in. Jeremy takes a simple random sample of 16 such men and notices that none of them are unusually tall or unusually short. He then calculates the average of the sample to be 67 in. and is planning on using this to find a 90% z-confidence interval for the true mean height. Can Jeremy use this information to find the z-confidence interval? Complete the following sentences. The population distribution is and the population standard deviation is Therefore, the sample to find a 90% z-confidence interval.
The ages of registered voters in Smith County are normally distributed with a population standard deviation of 3 years and an unknown population mean. A random sample of 18 voters is taken and results in a sample mean of 55 years. Find the margin of error for a 95% confidence interval for the population mean. z0.10z0.10 z0.05z0.05 z0.025z0.025 z0.01z0.01 z0.005z0.005 1.282 1.645 1.960 2.326 2.576 You may use a calculator or the common z values above. Round the final answer to two decimal places.
You are part of a trivia team and have tracked your team's performance since you started playing, so you know that your scores are normally distributed with u = 88 and a = 15 Recently, a new person joined the team, and you think the scores have changed Sample data is: n = 28, sample mean = 72 Assuming a two tailed test, What is the test statistic (Z)?
Can you solve this problem about the confidence interval?
Given two independent random samples with the following results: n1=12x‾1=73s1=27n1=12x‾1=73s1=27 n2=12x‾2=102s2=22n2=12x‾2=102s2=22 Use this data to find the 95%95% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed. Step 1 of 3 : Find the point estimate that should be used in constructing the confidence interval.
The following data represent the length of time, in days, to recovery for patients randomly treated with one of two medications to ciear up severe bladder infections. Find a 95% confidence interval for the difference u,-H, between in the mean recovery times for the two medications, assuming normal populations with equal variances. Medication 1 x, 13 s = 14 s =1.6 n, = 14 Medication 2 n211 X2= 16 Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table ofcritical values of the t-distribution The confidence interval is
A sample of n = 24 data values randomly selected from a normally distributed population has variance s = 21.7. Construct a 90% confidence interval for the population variance. Round your endpoints to one decimal place. < o?

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