The following reaction was performed in a sealed vessel at 783 °C: H2(g) + I2(g) =2H(g) Initially, only H2 and I2 were present at concentrations of H2] = 3.05M and a] = 2.20M . The equilibrium concentration of I2 is 0.0100 M. What is the equilibrium constant, K for the reaction at this temperature? %3D Express your answer numerically. > View Available Hint(s) Ενα ΑΣφ ΑΣΦ Ke
The following reaction was performed in a sealed vessel at 783 °C: H2(g) + I2(g) =2H(g) Initially, only H2 and I2 were present at concentrations of H2] = 3.05M and a] = 2.20M . The equilibrium concentration of I2 is 0.0100 M. What is the equilibrium constant, K for the reaction at this temperature? %3D Express your answer numerically. > View Available Hint(s) Ενα ΑΣφ ΑΣΦ Ke
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![M Review | Constants Periodic Table
The equilibrium constant, K, of a reaction at a
particular temperature is determined by the
concentrations or pressures of the reactants and
products at equilibrium.
Part B however, you will be given initial concentrations and only one equilibrium concentration. You must use this
data to find all three equilibrium concentrations before you can apply the formula for K
For a gaseous reaction with the general form
Part B
aA + 6B= cC + dD
The following reaction was performed in a sealed vessel at 783 °C:
the Ke and K, expressions are given by
H2 (g) + I2(g) = 2HI(g)
„lal.bl
[A]"B*
K. =
Initially, only H2 and I2 were present at concentrations of H2] = 3.05M and a]= 2.20M . The
equilibrium concentration of I2 is 0.0100 M. What is the equilibrium constant, K for the reaction at this
temperature?
(Pc(P)
Kp
%3D
(P.) (P)*
Express your answer numerically.
> View Available Hint(s)
The subscript c or p indicates whether K is
expressed in terms of concentrations or pressures.
Equilibrium-constant expressions do not include a
term for any pure solids or liquids that may be
involved since their composition does not change
throughout the reaction. The standard state of a
pure substance is the pure sibstance itself, and
although the quantity may change the sample
remain pure. The constant value is incorporated
into the value of K, and does not need to be
accounted for separately.
K =
Submit](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe17ee3d9-6ebe-435a-ba9d-3c68c44204c7%2F30236b3e-f70c-4a1f-b383-5d7ae10d64da%2F1ob0uwn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:M Review | Constants Periodic Table
The equilibrium constant, K, of a reaction at a
particular temperature is determined by the
concentrations or pressures of the reactants and
products at equilibrium.
Part B however, you will be given initial concentrations and only one equilibrium concentration. You must use this
data to find all three equilibrium concentrations before you can apply the formula for K
For a gaseous reaction with the general form
Part B
aA + 6B= cC + dD
The following reaction was performed in a sealed vessel at 783 °C:
the Ke and K, expressions are given by
H2 (g) + I2(g) = 2HI(g)
„lal.bl
[A]"B*
K. =
Initially, only H2 and I2 were present at concentrations of H2] = 3.05M and a]= 2.20M . The
equilibrium concentration of I2 is 0.0100 M. What is the equilibrium constant, K for the reaction at this
temperature?
(Pc(P)
Kp
%3D
(P.) (P)*
Express your answer numerically.
> View Available Hint(s)
The subscript c or p indicates whether K is
expressed in terms of concentrations or pressures.
Equilibrium-constant expressions do not include a
term for any pure solids or liquids that may be
involved since their composition does not change
throughout the reaction. The standard state of a
pure substance is the pure sibstance itself, and
although the quantity may change the sample
remain pure. The constant value is incorporated
into the value of K, and does not need to be
accounted for separately.
K =
Submit
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