Homework Help is Here – Start Your Trial Now!
Math
Probability
The following question is from a probability course: A mobile number starts with the digits 06, followed by eight digits from 0 to 9. Suppose we assume that every mobile number is equally probable. Show that the probability that someone has a mobile number whose last eight digits are all different from each other is ((10!)/(2!*(10^8))) if able please give some explanation with the taken steps, thank you in advance.

The following question is from a probability course: A mobile number starts with the digits 06, followed by eight digits from 0 to 9. Suppose we assume that every mobile number is equally probable. Show that the probability that someone has a mobile number whose last eight digits are all different from each other is ((10!)/(2!*(10^8))) if able please give some explanation with the taken steps, thank you in advance.

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
See similar textbooks
icon
Related questions
Question

The following question is from a probability course:

A mobile number starts with the digits 06, followed by eight digits from 0 to 9. Suppose we assume that every mobile number is equally probable. Show that the probability that someone has a mobile number whose last eight digits are all different from each other is ((10!)/(2!*(10^8)))

if able please give some explanation with the taken steps, thank you in advance.

Expert Solution
steps

Step by step

Solved in 3 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer