The following question is from a probability course: A mobile number starts with the digits 06, followed by eight digits from 0 to 9. Suppose we assume that every mobile number is equally probable. Show that the probability that someone has a mobile number whose last eight digits are all different from each other is ((10!)/(2!*(10^8))) if able please give some explanation with the taken steps, thank you in advance.

The following question is from a probability course: A mobile number starts with the digits 06, followed by eight digits from 0 to 9. Suppose we assume that every mobile number is equally probable. Show that the probability that someone has a mobile number whose last eight digits are all different from each other is ((10!)/(2!*(10^8))) if able please give some explanation with the taken steps, thank you in advance.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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